- 2073 Shrawan · 5 marks
Sharpness of resonance, forced e-m oscillation
Short answer
Sharpness describes resonance peak width; Q = ω₀L/R. For a series LCR circuit with E = E₀ cos ωt, current amplitude is I₀ = E₀ / √[R² + (ωL − 1/ωC)²]. Maximum I₀ = E₀/R occurs at ω = 1/√(LC). Smaller R gives sharper resonance.
Define sharpness of resonance. Derive the relation for current amplitude of forced e-m oscillation.
Sharpness of resonance
It describes how rapidly the current amplitude (or any response) drops when the driving frequency moves away from the resonant frequency. Small damping (small R) gives a sharp resonance. It is measured by the quality factor Q = ω0L/R = ω0/Δω, where Δω is the half-power bandwidth.
Current amplitude of forced e.m. oscillation
A series L, C, R circuit with applied emf E = E0 cos ωt.
~E0 cos ωt ---- L ---- R ---- C ---+
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- Equation: L d²q/dt² + R dq/dt + q/C = E0 cos ωt.
- In the steady state the charge oscillates at the driving frequency: q = q0 cos(ωt − φ).
- Substitute, write cos ωt = cos(ωt − φ)cosφ − sin(ωt − φ)sinφ, and equate coefficients:
q0 (1/C − Lω²) = E0 cosφ
q0 R ω = E0 sinφ
- Square and add:
q0 = E0 / {ω √[R² + (ωL − 1/ωC)²]}
- The current is i = dq/dt = −ωq0 sin(ωt − φ), so the current amplitude is I0 = ωq0:
I0 = E0 / √[R² + (ωL − 1/ωC)²] = E0/Z
The current lags the emf by ψ = φ − π/2, where tanψ = (ωL − 1/ωC)/R. 6. I0 is maximum (E0/R) when ωL = 1/ωC, i.e. ω = 1/√(LC). The smaller R is, the taller and sharper the peak of I0 against ω.
✓ Answer checked by Claude Opus 5.5 (high effort)
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