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Forced vibration amplitude and resonance

Short answer

Free vibration occurs at natural frequency without external force; forced vibration is driven by periodic force at driving frequency. Amplitude A = (F0/m)/√((ω0²-p²)²+4γ²p²) peaks at resonance p_r = √(ω0²−2γ²) with A_max = F0/(2mγ√(ω0²−γ²)). Sharpness is measured by quality factor Q = ω0/(2γ).

Distinguish between free and forced vibrations. Give the necessary theory of forced vibration (differential equation), determine the amplitude of oscillation and deduce the condition for resonance amplitude. Explain sharpness of resonance.

Free and forced vibrations

Free vibrationForced vibration
Body vibrates at its natural frequency after an initial disturbanceBody vibrates at the frequency of an external periodic force
No external force after startPeriodic force acts continuously
Amplitude falls if dampedAmplitude steady (after transients)
Example: pluck a stringExample: tuning fork on a table

Theory (differential equation)

Mass m, spring constant k, damping force −b v, driving force F0 cos pt:

m x'' + b x' + k x = F0 cos pt
x'' + 2γ x' + ω0² x = f0 cos pt

with 2γ = b/m, ω0² = k/m, f0 = F0/m.

Amplitude

Steady state: x = A cos(pt − φ). Substituting and comparing the coefficients of cos(pt − φ) and sin(pt − φ):

A (ω0² − p²) = f0 cosφ
A (2γ p)     = f0 sinφ
A = f0 / √[(ω0² − p²)² + 4γ²p²] ,   tanφ = 2γp/(ω0² − p²)

Amplitude resonance

A is maximum when D = (ω0² − p²)² + 4γ²p² is minimum. dD/d(p²) = −2(ω0² − p²) + 4γ² = 0:

p_r² = ω0² − 2γ²      (p_r < ω0)
A_max = f0 / (2γ √(ω0² − γ²))

Resonance condition: the driving frequency equals √(ω0² − 2γ²), very nearly the natural frequency if damping is small. For γ → 0, A becomes very large at p = ω0.

Sharpness of resonance

It is the rate at which the amplitude falls as p departs from p_r.

 A |      /\  small damping (sharp)
   |     /  \
   |    / __ \___ large damping (flat)
   |___/_/____\\___ p
        p_r
  • Small γ gives a tall, narrow peak (sharp); large γ gives a low, broad peak.
  • It is measured by the quality factor Q = ω0/2γ = ω0/Δω, where Δω is the half-power bandwidth.

✓ Answer checked by Claude Opus 5.5 (high effort)

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