- 2072 Kartik · 5 marks
Coherent sources and Newton's ring law
Short answer
Coherent sources emit with constant phase difference, obtained by division of wavefront (e.g., Young’s double slit) or amplitude (thin films). For Newton’s rings in reflected light, dark ring condition 2t = nλ with t ≈ r²/(2R) leads to D_n² = 4nλR, so D_n² ∝ n.
What are the coherent sources of light? How can such sources be developed in the lab? Show that the square of the diameters of the nth dark ring by the reflected light of Newton's ring is directly proportional to the natural number.
Coherent sources
Two sources are coherent if they emit light waves of the same frequency with a constant phase difference between them. Two independent ordinary sources are not coherent, because their atoms emit light in random, short bursts lasting only about 10⁻⁸ s, so the phase difference keeps changing.
How to obtain them
Both coherent sources are derived from one source:
- Division of wavefront: Young's double slit, Fresnel's biprism, Lloyd's mirror. The wavefront from a single slit is divided into two parts, which act as two (real or virtual) coherent sources.
- Division of amplitude: the beam is partly reflected and partly transmitted by a thin film, wedge or beam splitter (Newton's rings, Michelson interferometer).
D² ∝ n in Newton's rings
lens (radius R)
_______|_______
\ r | t /
________\____|_____/_____ glass plate
O film
- A plano-convex lens of radius of curvature R rests on a plane glass plate. At distance r from the contact point, the air film has thickness t.
- Geometry: R² = (R − t)² + r² → r² = 2Rt − t² ≈ 2Rt, so t = r²/(2R).
- In reflected light, ray 2 (reflected at the plate) gets an extra λ/2, so the path difference is 2t + λ/2 (normal incidence, air).
- Dark ring: 2t + λ/2 = (2n+1)λ/2 → 2t = nλ.
- Substitute t: r²/R = nλ → r² = nλR. With D = 2r:
D_n² = 4 n λ R
Since λ and R are constants, D_n² ∝ n: the squares of the diameters of the dark rings are in the ratio 1 : 2 : 3 ... of the natural numbers, so the rings crowd closer together as n increases. The centre (n = 0) is dark.
✓ Answer checked by Claude Opus 5.5 (high effort)
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