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Thin film interference by reflected light
Short answer
Coherent monochromatic sources with same polarization are needed. For a thin film of refractive index μ and thickness t, reflected light path difference is 2μt cos r, with an extra λ/2 from reflection at the top surface. Effective path difference Δ = 2μt cos r − λ/2. Bright: 2μt cos r = (2n+1)λ/2; dark: 2μt cos r = nλ.
Write down the conditions for interference of light. Give the necessary theory for interference in a thin film due to reflected light (derive the relations for interference by reflected light).
Conditions for interference
- The two sources must be coherent: a constant phase difference and the same frequency.
- They should emit light of the same wavelength (monochromatic) and the same state of polarization.
- The amplitudes should be nearly equal for good contrast.
- The sources must be narrow, and the path difference small (within the coherence length).
- The screen should be sufficiently far from the sources.
Thin film: reflected light
air: \ 1 / 1'
\ i /
-----------A-\\---C--------- top surface
film (μ) r \ / r t
-------------B------------- bottom surface
A parallel beam falls at angle i on a film of thickness t and refractive index μ; the angle of refraction is r. Ray 1 is reflected at A on the top surface. Ray 2 refracts at A, reflects at B on the bottom surface, and emerges at C parallel to ray 1.
- Optical path of ray 2 inside the film: μ(AB + BC)
- Draw CD perpendicular to the reflected ray 1. The path of ray 1 in air up to D is AD = AC sin i; also μ = sin i / sin r
- Geometry: AB = BC = t / cos r, and AC = 2t tan r
- Optical path difference: μ(2t/cos r) − 2t tan r sin i = 2μt/cos r − 2μt sin²r/cos r = 2μt cos r
- Reflection at the top surface (rarer to denser) gives an extra phase change of π, equivalent to a path of λ/2. Effective path difference: Δ = 2μt cos r − λ/2 (or +λ/2).
Conditions
- Bright (constructive): 2μt cos r − λ/2 = nλ → 2μt cos r = (2n+1) λ/2, n = 0, 1, 2 ...
- Dark (destructive): 2μt cos r − λ/2 = (2n+1)λ/2 → 2μt cos r = nλ
For normal incidence (r = 0): 2μt = (2n+1)λ/2 for bright and 2μt = nλ for dark. A very thin film (t << λ) looks dark in reflected light.
✓ Answer checked by Claude Opus 5.5 (high effort)
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