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Nusselt theory of film condensation

Short answer

Film condensation forms a continuous liquid layer with higher thermal resistance and lower h; dropwise condensation forms droplets that roll off, giving 5–10 times higher h but is difficult to sustain. Nusselt's theory assumes laminar film, pure saturated quiescent vapor, uniform wall temperature, conduction across film, and constant properties. The average heat transfer coefficient is: h_bar = 0.943 [ρ_l(ρ_l−ρ_v) g h'_fg k_l^3 / (μ_l L ΔT)]^{1/4}.

Distinguish between film and dropwise condensation. State the assumptions of Nusselt's theory of film condensation on a vertical plate and derive the expression for the average heat transfer coefficient.

Film and dropwise condensation

PointFilm condensationDropwise condensation
SurfaceWetted; liquid forms a continuous filmNot wetted (oily or coated); drops form and roll off
ResistanceFilm acts as thermal resistanceLittle film, bare surface exposed
hhLower5 to 10 times higher
OccurrenceUsual in industry (clean surfaces)Hard to maintain; needs promoters

Industrial condensers are designed for film condensation because it is the dependable condition.

Assumptions of Nusselt's theory

  1. Laminar film flow with constant fluid properties.
  2. Pure saturated vapour at rest, no shear at the liquid-vapour interface.
  3. Wall at uniform temperature Tw<TsatT_w < T_{sat}.
  4. Heat moves across the film by conduction only (linear temperature profile); no convection or inertia in the film.
  5. Subcooling of the liquid is included through hfg′=hfg+0.68cpl(Tsat−Tw)h'_{fg} = h_{fg}+0.68c_{pl}(T_{sat}-T_w); vapour density is small compared with liquid.

Derivation

Let the film thickness at height xx be δ\delta. Force balance on an element of liquid (gravity minus buoyancy balanced by viscous shear):

μld2udy2=−g(ρl−ρv)\mu_l\frac{d^2u}{dy^2} = -g(\rho_l-\rho_v)

With u=0u = 0 at y=0y = 0 (wall) and du/dy=0du/dy = 0 at y=δy = \delta:

u=g(ρl−ρv)μl(δy−y22)u = \frac{g(\rho_l-\rho_v)}{\mu_l}\left(\delta y-\frac{y^2}{2}\right)

Mass flow per unit width: m˙=∫0δρlu dy=ρlg(ρl−ρv)δ33μl\dot m = \int_0^\delta\rho_l u\,dy = \dfrac{\rho_l g(\rho_l-\rho_v)\delta^3}{3\mu_l}.

Heat transferred by conduction across the film equals latent heat released by the extra condensate dm˙d\dot m in length dxdx:

kl(Tsat−Tw)δdx=hfg′ dm˙=hfg′ρlg(ρl−ρv)δ2μldδ\frac{k_l(T_{sat}-T_w)}{\delta}dx = h'_{fg}\,d\dot m = h'_{fg}\frac{\rho_l g(\rho_l-\rho_v)\delta^2}{\mu_l}d\delta

Integrating from δ=0\delta = 0 at x=0x = 0:

δ=[4μlkl(Tsat−Tw) xgρl(ρl−ρv)hfg′]1/4\delta = \left[\frac{4\mu_lk_l(T_{sat}-T_w)\,x}{g\rho_l(\rho_l-\rho_v)h'_{fg}}\right]^{1/4}

The local coefficient is hx=kl/δh_x = k_l/\delta. The average over height LL is hˉ=43hx=L\bar h = \frac{4}{3}h_{x=L}:

hˉ=0.943[ρl(ρl−ρv) g hfg′ kl3μl L (Tsat−Tw)]1/4\bar h = 0.943\left[\frac{\rho_l(\rho_l-\rho_v)\,g\,h'_{fg}\,k_l^3}{\mu_l\,L\,(T_{sat}-T_w)}\right]^{1/4}

Properties of liquid are taken at film temperature (Tsat+Tw)/2(T_{sat}+T_w)/2 and hfgh_{fg} at TsatT_{sat}.

✓ Answer checked by Claude Sonnet 5.5

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