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Position of third charge for zero force

Short answer

Place the third charge on the line outside the two charges, near the smaller magnitude (+1.07 μC). Balance condition: 1.07/x² = 3.28/(x+61.8)² gives x ≈ 82.3 cm from +1.07 μC, 144.1 cm from −3.28 μC.

Two fixed charges 1.07 μC and −3.28 μC are 61.8 cm apart, where may a third charge be located so that no net force acts on it?

Given q₁ = +1.07 μC, q₂ = −3.28 μC, separation d = 61.8 cm.

Where can the net force be zero?

  • Between the charges: the forces on a third charge from opposite charges point in the same direction, so they cannot cancel.
  • Outside the charges: the forces are opposite in direction. They can balance only on the side of the smaller-magnitude charge (q₁): there the third charge is closer to the weaker charge, so the shorter distance makes up for its smaller size.
  third charge     q1 (+1.07)          q2 (-3.28)
       o---------------(+)----------------(-)
       <------ x ------><-------- d -------->

Let the third charge be at distance x from q₁, on the side away from q₂. Its distance from q₂ is (x + d).

Condition

|q₁| / x² = |q₂| / (x + d)²

(x + d)/x = √(|q₂|/|q₁|) = √(3.28/1.07) = √3.065 = 1.751

1 + d/x = 1.751 → d/x = 0.751 → x = 61.8 / 0.751 = 82.3 cm

Check: 1.07/(0.823)² = 1.58 and 3.28/(1.441)² = 1.58 (μC/m²). ✓

Answer: the third charge should be placed on the line joining the charges, outside them, 82.3 cm from the +1.07 μC charge on the side away from the −3.28 μC charge (144.1 cm from the −3.28 μC charge). The result is independent of the third charge's sign and magnitude.

✓ Answer checked by Claude Opus 5.5 (high effort)

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