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N-channel depletion MOSFET construction, working
Short answer
Has an n-channel diffused in p-substrate under a SiO₂ layer and metal gate. At VGS = 0, ID = IDSS. Negative VGS depletes channel (pinch-off at VP), positive VGS enhances it. Used in depletion and enhancement modes, follows ID = IDSS (1 − VGS/VP)² in saturation.
Describe the construction and working principle of n-channel depletion type MOSFET with necessary diagrams.
The n-channel depletion MOSFET (D-MOSFET) has a physical n-channel built between source and drain, so current flows even at VGS = 0. A gate voltage can either deplete the channel (negative VGS) or enhance it (positive VGS). So it can work in both depletion and enhancement modes.
Construction
- A p-type substrate.
- Two heavily doped n⁺ regions (source and drain) diffused in the substrate.
- A thin lightly doped n-type channel diffused between the source and drain, below the oxide.
- A thin SiO₂ layer over the channel, with a metal gate on top (insulated from the channel).
- Substrate (body) usually joined to the source.
S G D
| +-----+ |
---+ |metal| +---
| n+| +-----+ | n+|
| |~~ n-channel ~~| |
| p substrate |
+----------B------------+
Working principle
- VGS = 0: with VDS applied, electrons flow through the n-channel from source to drain. Drain current is IDSS.
- Negative VGS (depletion mode): the negative gate repels electrons from the channel (holes are induced), so the channel becomes narrower and ID decreases. At VGS = VP (pinch-off, a negative value), the channel is fully depleted and ID ≈ 0.
- Positive VGS (enhancement mode): the positive gate attracts more electrons into the channel, so the channel widens and ID rises above IDSS.
Characteristics
Shockley equation (saturation region): ID = IDSS (1 − VGS/VP)²
ID ID
| VGS=+1 ___ | /
| VGS= 0 ___ IDSS | IDSS _.--'
| VGS=-1 ___ | .-'
| VGS=-2 ___ |/
+----------------- VDS +---+--------- VGS
Drain characteristic VP 0
- VGS < VP: cut-off.
- Ohmic region at low VDS, saturation at higher VDS.
Comparison with E-MOSFET: D-MOSFET has a built-in channel, conducts at VGS = 0 (normally-ON), and works with both polarities of VGS; E-MOSFET has no channel at VGS = 0 and needs VGS > VT.
Applications: RF amplifiers, input stages of high-impedance amplifiers, and constant current sources.
✓ Answer checked by Claude Opus 5.5 (high effort)
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