- 2081 Chaitra (new course) · 6 marks
n-channel depletion MOSFET operation
Short answer
An n‑channel D‑MOSFET has a built‑in n‑channel. At V_GS = 0, I_D = I_DSS. Negative V_GS depletes the channel (I_D decreases; cut‑off at V_P). Positive V_GS enhances it (I_D > I_DSS). I_D = I_DSS (1 − V_GS/V_P)^2.
Explain the operation of n-channel depletion MOSFET with the necessary diagrams.
An n-channel depletion MOSFET (D-MOSFET) has a channel built in during manufacture, so drain current flows even at V_GS = 0. It can work in two modes: depletion mode (V_GS negative) and enhancement mode (V_GS positive).
Construction
S G D
| __|__ |
___|___ |metal| ___|___
| n+ ||=SiO2=|| n+ |
|_______|________|_______|
| diffused n-channel |
| |
| p-type substrate |
|__________________________|
|
SS (body, tied to S)
- A lightly doped p-type substrate forms the body.
- Two heavily doped n+ regions form the source and drain.
- A thin n-type channel is diffused between them, linking source and drain.
- A thin SiO₂ layer insulates the metal gate from the channel, so gate current ≈ 0 and input resistance is very high.
Operation
1. V_GS = 0: with a positive V_DS, electrons flow from source to drain through the existing n-channel. The current at V_GS = 0 with the channel pinched off is I_DSS.
2. V_GS negative (depletion mode): the negative gate repels electrons from the channel and attracts holes from the p-substrate, which recombine with electrons. The number of free electrons in the channel falls (the channel is depleted), so I_D decreases. At V_GS = V_P (pinch-off voltage, e.g. −4 V) the channel is fully depleted and I_D = 0.
3. V_GS positive (enhancement mode): the positive gate attracts more electrons (minority carriers) from the substrate into the channel. The channel becomes richer in carriers and I_D rises above I_DSS. This is possible because the gate is insulated, so no gate current flows. (A JFET cannot do this.)
4. Effect of V_DS: as V_DS rises, the channel narrows near the drain because the gate-to-drain voltage becomes more negative. At V_DS = V_GS − V_P the channel pinches off at the drain end, and I_D becomes nearly constant (saturation).
Characteristics
In saturation the transfer characteristic follows Shockley's equation: I_D = I_DSS (1 − V_GS/V_P)².
Transfer Drain
I_D I_D | ______ +1 V (enh.)
| / | /______ 0 V (I_DSS)
| / | /_______ −1 V
I_DSS * |/________ −2 V (depl.)
| / +------------- V_DS
|_/______ V_GS
V_P 0 +
Symbol (n-channel D-MOSFET):
D
|
G ||--+ solid line =
||<-+-- SS built-in channel
||--+
S
Summary
| V_GS | Mode | I_D |
|---|---|---|
| Positive | Enhancement | > I_DSS |
| 0 | — | = I_DSS |
| Negative (> V_P) | Depletion | < I_DSS |
| = V_P | Cutoff | 0 |
D-MOSFETs are used in RF amplifiers and as constant-current loads because they conduct at zero bias and accept both polarities of gate voltage.
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- n-channel enhancement MOSFET · Fundamental of Electrical and Electronics Engineering, chapter 5
- N-channel depletion MOSFET construction, working · Basic Electronics Engineering, chapter 3 · asked 9×
- Depletion MOSFET Q-points (IDSS 10 mA, VP -4 V) · Electronics Devices and Circuit, chapter 3
- N-channel enhancement MOSFET construction, working · Basic Electronics Engineering, chapter 3 · asked 9×
- n-channel E-MOSFET construction and working · Electronics Devices and Circuit, chapter 3 · asked 9×
All Fundamental of Electrical and Electronics Engineering chapter 5 questions →