- 2081 Baishakh (new course) · 4 marks
n-channel enhancement MOSFET
Short answer
An n‑channel E‑MOSFET has a p‑substrate, n+ source/drain, and insulated gate with no built‑in channel. At V_GS = 0 it is off. For V_GS ≥ V_T, an inversion n‑channel forms; I_D increases with V_GS. In saturation, I_D = k(V_GS − V_T)^2.
Describe the construction and working principle of n-channel enhancement type MOSFET.
An n-channel enhancement MOSFET (E-MOSFET) is a field-effect transistor in which no channel exists at V_GS = 0; a channel is created ("enhanced") only when a positive gate voltage above the threshold V_T is applied.
Construction
S G D
| __|__ |
___|___ |metal| ___|___
| n+ ||=SiO2=|| n+ |
|_______| ~~~~ |_______|
| induced n-channel |
| p-type substrate |
|__________________________|
|
SS (body)
- A lightly doped p-type substrate forms the body.
- Two heavily doped n+ regions are diffused into it to form the source and drain.
- A thin layer of silicon dioxide (SiO₂) insulates the substrate surface; a metal (or polysilicon) gate is placed on top. The gate is insulated, so gate current is practically zero (very high input resistance, about 10¹⁰–10¹⁵ Ω).
- There is no built-in channel between source and drain. The substrate is usually connected to the source.
Working principle
- V_GS = 0: source and drain are separated by p-type material, forming two back-to-back pn junctions. Only a tiny leakage current flows, so I_D ≈ 0 (device OFF).
- 0 < V_GS < V_T: the positive gate repels holes from the region under the oxide, leaving a depletion region of negative ions. Still no conduction.
- V_GS ≥ V_T (threshold, typically 1–3 V): enough electrons (minority carriers of the p-substrate) are attracted under the gate to form a thin n-type inversion layer. This channel connects source and drain, and with V_DS > 0, electrons flow from source to drain: I_D flows.
- Larger V_GS → thicker channel → larger I_D. Hence the name "enhancement".
- Effect of V_DS: as V_DS increases, the channel near the drain narrows. When V_DS ≥ V_GS − V_T, the channel is pinched off at the drain end and I_D saturates.
In saturation: I_D = k (V_GS − V_T)², valid for V_GS > V_T.
I_D | ______ V_GS = 6 V
| _/______ V_GS = 5 V
| _/________ V_GS = 4 V
|_______/__________ V_GS ≤ V_T
0 V_DS
E-MOSFETs are used as switches in digital ICs (CMOS) because they are normally OFF.
✓ Answer checked by Claude Opus 5.5 (high effort)
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