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Resistor value from colour code

Short answer

a) Red-Orange-Green-Silver: 2, 3, ×10⁵, ±10% → 2.3 MΩ ±10%. b) Yellow-Black-Gold-Gold: 4, 0, ×0.1, ±5% → 4 Ω ±5%.

Find the value of resistor from following colour code. a) Red Orange Green Silver b) Yellow Black Gold Gold

Colour values: Black 0, Brown 1, Red 2, Orange 3, Yellow 4, Green 5, Blue 6, Violet 7, Grey 8, White 9. Multiplier: Gold ×0.1, Silver ×0.01. Tolerance: Gold ±5%, Silver ±10%.

a) Red, Orange, Green, Silver

  • 1st digit: Red = 2
  • 2nd digit: Orange = 3
  • Multiplier: Green = ×10⁵
  • Tolerance: Silver = ±10%

R = 23 × 10⁵ = 2,300,000 Ω

Answer: 2.3 MΩ ± 10% (range 2.07 MΩ to 2.53 MΩ)

b) Yellow, Black, Gold, Gold

  • 1st digit: Yellow = 4
  • 2nd digit: Black = 0
  • Multiplier: Gold = ×0.1
  • Tolerance: Gold = ±5%

R = 40 × 0.1 = 4 Ω

Answer: 4 Ω ± 5% (range 3.8 Ω to 4.2 Ω)

✓ Answer checked by Claude Opus 5.5 (high effort)

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