- 2071 Bhadra · 2.5 marks
Cu(I) diamagnetic, Cu(II) paramagnetic
Short answer
Cu(I) has a 3d10 configuration with no unpaired electrons, making it diamagnetic. Cu(II) is 3d9 with one unpaired electron, making it paramagnetic with a magnetic moment of 1.73 BM.
Give reason: Cu(I) is diamagnetic whereas Cu(II) is paramagnetic.
Magnetic behaviour depends on unpaired electrons.
- Cu⁺ (Z = 29) has the configuration [Ar] 3d¹⁰. All ten d electrons are paired, so there is no unpaired electron and Cu(I) is diamagnetic.
- Cu²⁺ has the configuration [Ar] 3d⁹. One d orbital holds a single electron, so there is one unpaired electron and Cu(II) is paramagnetic (μ = √(1×3) = 1.73 BM).
Therefore Cu(I) compounds are diamagnetic and Cu(II) compounds are paramagnetic.
✓ Answer checked by Claude Opus 5.5 (high effort)
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