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Displacement work and polytropic process
Short answer
Displacement work is W = ∫ P dV. For a polytropic process PV^n = C, W = (P₂V₂ - P₁V₁)/(1-n) = (P₁V₁ - P₂V₂)/(n-1); for ideal gas, W = mR(T₁-T₂)/(n-1).
Derive the mathematical expression of displacement work and simplify it for a polytropic process.
Displacement work
Consider a gas of pressure P in a frictionless piston-cylinder, piston area A. When the piston moves a small distance dx, the force on it is PA, so
δW = F dx = (P A) dx = P dV (since A dx = dV)
For a process 1 → 2, the displacement (boundary) work is
W₁₂ = ∫₁² P dV
It equals the area under the process curve on the P-V diagram. It is positive for expansion (dV > 0) and negative for compression.
Polytropic process (PVⁿ = C)
P = C / Vⁿ, with C = P₁V₁ⁿ = P₂V₂ⁿ.
W₁₂ = ∫₁² C V⁻ⁿ dV = C [V¹⁻ⁿ/(1 − n)]₁²
= (C V₂¹⁻ⁿ − C V₁¹⁻ⁿ)/(1 − n)
Using C V₂¹⁻ⁿ = P₂V₂ and C V₁¹⁻ⁿ = P₁V₁:
W₁₂ = (P₂V₂ − P₁V₁)/(1 − n) = (P₁V₁ − P₂V₂)/(n − 1) (n ≠ 1)
For an ideal gas (PV = mRT):
W₁₂ = m R (T₁ − T₂)/(n − 1)
For n = 1 (isothermal): W₁₂ = P₁V₁ ln(V₂/V₁).
✓ Answer checked by Claude Opus 5.5 (high effort)
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