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Short note: Relief displacement expression

Short answer

Relief displacement is the radial image shift on a vertical photo due to height h above datum: d = r h / H, where r is radial distance from principal point and H is flying height. It is derived from similar triangles: r = fR/(H–h), r₀ = fR/H, giving d = r – r₀ = r h / H.

Describe relief displacement and derive its expression in case of vertical photogrammetry.

Relief displacement is the radial shift in the position of the image of a point on a vertical photograph caused by its elevation above or below the datum. Points above the datum are displaced away from the principal point (which is also the nadir point on a vertical photo); points below the datum are displaced towards it. Points lying on the datum are not displaced.

          O  (camera)
         /|\
      f / | \
       /  |  \ H
    a'  a |   \
   -------n-----  photo plane
            \ h  A
 ground   --A0--n'--     datum

Expression

Let A be the top of an object of height hh above the datum, A₀ its base on the datum, HH the flying height above the datum, and RR the horizontal ground distance from the nadir point to A. Let aa and a0a_0 be the images of A and A₀, and rr and r0r_0 their radial distances on the photo from the nadir point (the principal point of a vertical photo).

By similar triangles in the camera:

r=fRH−h,r0=fRHr = \frac{fR}{H-h},\qquad r_0 = \frac{fR}{H}

Relief displacement d=r−r0d = r - r_0:

d=fR[1H−h−1H]=fRhH(H−h)=r hHd = fR\left[\frac{1}{H-h}-\frac{1}{H}\right] = \frac{fRh}{H(H-h)} = \frac{r\,h}{H}

since r=fR/(H−h)r = fR/(H-h). So

d=r hHd = \frac{r\,h}{H}

Conclusions: the displacement increases with the radial distance rr and the height hh, and decreases as the flying height HH increases; it is zero at the principal point.

✓ Answer checked by Claude Opus 5.5 (high effort)

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