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Expression for scale of vertical photograph

Short answer

From similar triangles, the scale S of a vertical photograph equals the ratio of photo distance to ground distance: S = f/(H-h), where f is focal length, H is flying height above datum, and h is ground elevation. For level ground at datum, S = f/H.

Determine the expression for the scale of vertical photograph.

The scale of a photograph is the ratio of a length measured on the photograph to the corresponding length on the ground.

        O  (exposure station)
       /|\
    f / | \
     /  |  \
   a----n----b    photo plane
        |
   H-h  |
        |
   A----N----B    ground at height h
   -----------    datum

Derivation

Let O be the lens centre, ff the focal length, HH the flying height above datum, and A and B two ground points at elevation hh above the datum, whose images are aa and bb on a vertical photo. The line abab on the photo is parallel to ABAB on the ground, as the camera axis is vertical.

Triangles OabOab and OABOAB are similar. The perpendicular height of O above the plane of abab is ff and above the ground plane AB is (H−h)(H-h). Hence

abAB=fH−h\frac{ab}{AB} = \frac{f}{H-h} S=fH−h\boxed{S = \frac{f}{H-h}}

Notes

  • For flat ground at the datum (h=0h = 0): S=f/HS = f/H.
  • If the ground is not level, the scale is different for each elevation; the average scale uses the mean ground elevation havh_{av}: Sav=f/(H−hav)S_{av} = f/(H-h_{av}).
  • Scale can also be found from the map: S=photo distancemap distance×map scaleS = \dfrac{\text{photo distance}}{\text{map distance}}\times\text{map scale}.
  • Example: f=152f = 152 mm, H=3000H = 3000 m above a ground at 500 m gives S=0.152/2500=1:16 447S = 0.152/2500 = 1:16\,447.

✓ Answer checked by Claude Opus 5.5 (high effort)

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