Skip to main content

Power vs refrigeration cycle; Rankine components and diagrams

Short answer

Power cycles produce net work output, operate clockwise; refrigeration cycles absorb heat from a cold space, operate anticlockwise. Rankine cycle components: pump, boiler, turbine, condenser. T-s diagram shows isentropic compression (pump), constant pressure heat addition (boiler), isentropic expansion (turbine), constant pressure condensation.

Differentiate between power cycle and refrigeration cycle. Sketch components, P-v and T-s diagrams for Rankine cycle.

Power cycle versus refrigeration cycle

PointPower cycleRefrigeration cycle
PurposeConvert heat into net workRemove heat from a cold space
Direction on P-v / T-sClockwiseAnticlockwise
Net workOutput (W_net > 0)Input (W_net < 0)
Heat flowQ_H absorbed at high T, Q_L rejected at low TQ_L absorbed at low T, Q_H rejected at high T
PerformanceThermal efficiency η = W/Q_HCOP = Q_L/W
Valueη < 1COP can be > 1
ExamplesRankine, Otto, Diesel, BraytonVapour-compression, reversed Brayton
DeviceHeat engineRefrigerator or heat pump

Rankine cycle components

        Boiler (Q_in)
     2 +----------+ 3
       |          |
     Pump        Turbine --> W_out
       |          |
     1 +----------+ 4
       Condenser (Q_out)
  • Boiler (with superheater): heats the water at constant pressure to steam (2-3).
  • Turbine: expands the steam isentropically and produces work (3-4).
  • Condenser: condenses the exhaust at constant pressure to saturated liquid (4-1).
  • Pump: raises the liquid pressure isentropically (1-2).

Diagrams

 T-s diagram                        P-v diagram
 T                                  P
 |                       3          |  2 ____________________ 3
 |           .-'''-.   .'|          |  |                       \
 |         .'       '.'  |          |  |                        '.
 |   2'  /____________3' |          |  |                          '-.
 |      /              \ |          |  1 _________________________ 4
 |     /                \|          +----------------------------------> v
 |  2 /                  |\
 |  1/___________________4 \
 |  /                       \
 +-----------------------------> s
 (2 lies just above 1; 2'-3' boiling, 3'-3 superheating)

Efficiency: η = [(h₃ − h₄) − (h₂ − h₁)]/(h₃ − h₂).

✓ Answer checked by Claude Opus 5.5 (high effort)

All Fundamental of Thermodynamics & Heat Transfer chapter 6 questions →