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Convergence of 1+1²/2²+2²/3³+...
Short answer
Diverges. General term uₙ = nⁿ/(n+1)ⁿ⁺¹; limit comparison with 1/n gives 1/e, and the harmonic series diverges.
Determine whether the following series is convergent or divergent: 1 + 1²/2² + 2²/3³ + 3³/4⁴ + 4⁴/5⁵ + ...
The series is 1 + 1²/2² + 2²/3³ + 3³/4⁴ + 4⁴/5⁵ + …
The pattern of the terms after the first: 1/4, 4/27, 27/256, 256/3125, so the general term is
uₙ = nⁿ/(n + 1)ⁿ⁺¹, n = 1, 2, 3, … (with 1 as the first term, n = 0)
Write uₙ in a convenient form
uₙ = (1/(n+1)) · (n/(n+1))ⁿ = (1/(n+1)) · (1 + 1/n)⁻ⁿ
Since (1 + 1/n)ⁿ → e, we have (1 + 1/n)⁻ⁿ → 1/e.
Limit comparison test with vₙ = 1/n
uₙ/vₙ = (n/(n+1)) (1 + 1/n)⁻ⁿ → 1 · (1/e) = 1/e
This limit is finite and non-zero. Σ 1/n is the harmonic series, which diverges, so Σ uₙ also diverges.
(The ratio test is inconclusive here: uₙ₊₁/uₙ → 1.)
Answer: the series diverges.
✓ Answer checked by Claude Opus 5.5 (high effort)
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