- 2081 Baishakh · 8+2 marks
Crank AB 5 rad/s, piston velocity
Short answer
Using relative velocity equations and the horizontal slider condition, v_C = 3.00 m/s towards A, ω_BC = 10.00 rad/s clockwise. Coriolis acceleration is the term 2ω × v_rel that arises when a point moves relative to a rotating frame; it is perpendicular to the relative velocity.
Crank AB rotates with a constant angular velocity of 5 rad/s. Determine the velocity of piston C and the angular velocity of link BC at the instant . Define coriolis acceleration. [Figure: crank AB = 600 mm at angle to the horizontal, link BC = 300 mm, piston C sliding horizontally, 150 mm offset between line of A and slider line.]
Assume the crank turns counter-clockwise at rad/s, with as origin, above and to the right of , and the slider line m above with to the right of (the magnitudes of the answers are the same for the other sense of rotation).
Geometry
is m above the slider line, so and (link slopes down to the right):
Velocities
The slider moves horizontally, so the component of is zero:
Answer: m/s (horizontal, towards ), rad/s clockwise.
Coriolis acceleration
Coriolis acceleration is the extra acceleration a point has when it moves relative to a rotating (moving) frame or body. If a point moves with relative velocity on a body rotating with angular velocity , then
where is the acceleration of the coincident point of the rotating body and is the acceleration of relative to the body. The term is the Coriolis acceleration. Its magnitude is and its direction is that of rotated through in the sense of . It exists only when the point slides on the rotating body (for example a collar sliding on a rotating arm, or a slider in a slotted rotating link); it is zero for two points fixed in the same rigid body, such as the crank pin and piston pin of a connecting rod.
✓ Answer checked by Claude Opus 5.5 (high effort)
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