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Explain general plane motion with example

Short answer

General plane motion is motion where all particles stay in parallel planes, combining translation of a reference point and rotation about it. For two points, v_B = v_A + ω×r_B/A, a_B = a_A + α×r_B/A - ω² r_B/A. Example: a rolling wheel, where the centre translates and the wheel rotates.

Explain general plane motion of rigid bodies with suitable example.

General plane motion (GPM) is the motion of a rigid body in which every particle stays in a plane parallel to a fixed plane, and the motion is neither pure translation nor pure rotation about a fixed axis. It is the sum of (i) a translation of a chosen reference point and (ii) a rotation of the body about that point.

For two points AA and BB of the same rigid body:

v⃗B=v⃗A+ω⃗×r⃗B/A,a⃗B=a⃗A+α⃗×r⃗B/A−ω2r⃗B/A\vec v_B = \vec v_A + \vec\omega \times \vec r_{B/A}, \qquad \vec a_B = \vec a_A + \vec\alpha \times \vec r_{B/A} - \omega^2 \vec r_{B/A}

Here vB/A=ω rB/Av_{B/A} = \omega\, r_{B/A} is perpendicular to ABAB, and aB/Aa_{B/A} has a tangential part αr\alpha r and a normal part ω2r\omega^2 r towards AA.

Examples

  • A wheel rolling on the road: the centre translates while the wheel rotates about the centre.
  • The connecting rod of an engine: end AA (crank pin) moves on a circle, end BB (piston) moves in a straight line.
  • A ladder sliding down a wall.

Worked example. For a wheel of radius rr rolling without slipping with centre speed vv: the centre OO translates with vv and the wheel rotates with ω=v/r\omega = v/r. The top point has vtop=v+ωr=2vv_{top} = v + \omega r = 2v and the contact point has vcontact=v−ωr=0v_{contact} = v - \omega r = 0, so the contact point is the instantaneous centre.

        top: 2v ->
         .---.
   v ->  | O |
         '---'
     contact point: v = 0

✓ Answer checked by Claude Opus 5.5 (high effort)

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