- 2081 Bhadra · 4 marks
Closed loop reduces internal disturbances
Short answer
Closed-loop reduces internal disturbances because feedback divides the effect of parameter variations and internal noise by (1+GH). For a disturbance D entering between G1 and G2, the output becomes G2D/(1+G1G2H), which is much smaller than the open-loop output G2D when loop gain is high.
Justify that the closed loop system reduces effect of internal disturbances in the system.
Internal disturbances are changes inside the system itself: variation of plant parameters (ageing, temperature, wear, supply changes) and internal noise. Feedback reduces their effect because the output is measured and the error is corrected.
1. Parameter variation
The sensitivity of the overall gain to a change in is
- Open loop: , so (a 10% change in gives a 10% change in output).
- Closed loop: , so and
Since , the effect of a change in is reduced by the factor . (With , a 10% change in changes the output by only 0.1%.)
2. Disturbance generated inside the plant
Let the disturbance enter between two forward blocks (controller) and (plant).
- Open loop: .
- Closed loop (feedback ), with (superposition):
The disturbance output is divided by . If , , which is very small for large .
Example
A DC motor's armature resistance rises as it heats. In open loop the speed falls in proportion. With tacho feedback and loop gain , the change in speed is only of the open-loop change.
Hence the closed-loop system is far less affected by internal disturbances, as long as the loop gain is high and the sensor itself is accurate (the sensitivity to is ).
✓ Answer checked by Claude Opus 5.5 (high effort)
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