Skip to main content

Control type for constant-speed actuator

Short answer

Use a closed-loop speed control system with a PI controller. It rejects load disturbances (steady-state error becomes zero due to integral action), reduces sensitivity to parameter variations, and speeds up response by reducing the motor time constant.

As a control engineer, you are required to control the actuator of a rotating system to get constant speed. Which type of control system will you suggest and why?

I would use a closed-loop (feedback) speed control system with a speed sensor (tachogenerator or encoder) and a PI controller.

 ωref +    e  +----+  +-----+ Va +-------+  ω
 ---->(Σ)---->| PI |->|Amp/ |--->| Motor |-+-->
      ^ -     +----+  |drive|    | +load | |
      |               +-----+    +-------+ |
      |    +------------+            ^ T_L |
      +----| Tacho  Kg  |<-----------------+
           +------------+

Why closed loop

  1. Load disturbance rejection: the load torque TLT_L changes the speed. In closed loop the speed change is divided by (1+K)(1+K), where KK is the loop gain; with the integral term, the steady-state speed error for a step change in load becomes zero.
  2. Insensitive to parameter changes: armature resistance rises with heating and the supply voltage varies; the sensitivity of speed to these is 1/(1+GH)1/(1+GH) instead of 1.
  3. Faster response: the motor time constant τm\tau_m becomes τm/(1+K)\tau_m/(1+K), so the speed recovers quickly after a disturbance.
  4. Accurate tracking of the set speed, needed in conveyors, paper mills, fans and pumps.

Why not open loop

An open-loop drive applies a fixed voltage. Its speed is ω=V−IaRaKb\omega = \dfrac{V - I_aR_a}{K_b}, so it falls whenever the load (and hence IaI_a) increases, and it cannot correct the drop.

Why PI

Proportional control alone leaves a steady-state error 1/(1+Kp)1/(1+K_p); the integral action removes it. A derivative term is usually not needed for speed loops and it amplifies tacho noise. The gains are chosen to give a fast response with small overshoot.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Control Systems chapter 1 questions →