- 2082 Baisakh · 6 marks
Feedback effect in DC motor speed control
Short answer
In open-loop, the motor’s speed drops directly with load torque and changes with parameter variations, with time constant tau_m. Closed-loop (with tachogenerator feedback) reduces the time constant to tau_m/(1+K) and the speed drop due to load torque to K_L T_L/(1+K), improving speed regulation and making it less sensitive to parameter changes, where K = amplifier gain times motor and tacho constants.
How would you consider the effect of feedback in speed control of an armature-controlled DC motor in comparison to open loop? Elaborate analytically.
Feedback (a tachogenerator measuring the speed) makes an armature-controlled DC motor respond faster and keeps its speed nearly constant despite load and parameter changes.
Open-loop model
Motor equations ( neglected): , . Hence
Steady-state speed drop on load: . Any change in , or changes the speed directly.
Closed-loop scheme
ωr + e +-----+ Va +-------+ ω
--->(Σ)---->| KA |--->| Motor |---+--->
^ - +-----+ +-------+ |
| +-------+ |
+------| Kg |<-------------+
| tacho |
+-------+
With amplifier gain and tacho constant , the loop gain is :
Comparison
| Quantity | Open loop | Closed loop |
|---|---|---|
| Time constant | ||
| Speed drop for load | ||
| Sensitivity to | 1 | |
| Gain |
- Faster response: the time constant is reduced by .
- Better speed regulation: the load-torque disturbance causes a speed drop times smaller.
- Less sensitivity to changes in (heating), flux or friction.
- Cost: lower overall gain (made up by ), a tachogenerator is needed, and with armature inductance included, very high can cause oscillation.
Example: with , a 100 rpm open-loop drop on load becomes only 5 rpm.
✓ Answer checked by Claude Opus 5.5 (high effort)
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