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K for sustained oscillation of k/[s(s+3)(s²+s+1)]

Short answer

Set the s¹ row of the Routh array to zero to find the marginal gain. Sustained oscillation occurs at k = 2.4375 with frequency ω = 0.866 rad/s.

The open loop transfer function of a unity feedback system is given by G(s) = k/[s(s+3)(s²+s+1)]. Determine the value of k that will cause sustained oscillation in the closed loop system. Also determine the oscillation frequency.

Sustained oscillation occurs at the marginal value of kk, where the s1s^1 row of the Routh array is zero. The auxiliary equation from the s2s^2 row then gives the frequency.

Characteristic equation

s(s+3)(s2+s+1)+k=0s4+4s3+4s2+3s+k=0\begin{aligned} s(s+3)(s^2+s+1) + k &= 0 \\ s^4 + 4s^3 + 4s^2 + 3s + k &= 0 \end{aligned}

Routh array

RowCol 1Col 2Col 3
s4s^414kk
s3s^3430
s2s^24(4)−1(3)4=134\frac{4(4)-1(3)}{4}=\frac{13}{4}kk
s1s^1134(3)−4k134=3−16k13\frac{\frac{13}{4}(3)-4k}{\frac{13}{4}}=3-\frac{16k}{13}0
s0s^0kk

For stability: 3−16k13>03-\frac{16k}{13}>0 and k>0k>0, so 0<k<3916=2.43750 < k < \frac{39}{16} = 2.4375.

Value of k for sustained oscillation

3−16k13=0⇒k=3916=2.43753 - \frac{16k}{13} = 0 \Rightarrow k = \frac{39}{16} = 2.4375

Oscillation frequency

Auxiliary equation:

134s2+k=0134s2+3916=0s2=−34⇒s=±j0.866\begin{aligned} \frac{13}{4}s^2 + k &= 0 \\ \frac{13}{4}s^2 + \frac{39}{16} &= 0 \\ s^2 &= -\frac{3}{4} \Rightarrow s = \pm j0.866 \end{aligned}

Check: at k=2.4375k=2.4375 the roots are ±j0.866\pm j0.866, −2.866-2.866 and −1.134-1.134.

Answer: k=2.4375k = 2.4375 gives sustained oscillation at ω=0.866\omega = 0.866 rad/s.

✓ Answer checked by Claude Opus 5.5 (high effort)

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