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Angle criterion for root locus

Short answer

The root locus passes through a point if the sum of angles from all open-loop zeros minus the sum from all open-loop poles equals ±(2q+1)180°. Vectors are drawn from each pole and zero to the test point; if the net angle is an odd multiple of 180°, the point is on the locus.

Describe angle criteria for a point in s-plane such that the root locus would cross through the point.

The root locus passes through a point s1s_1 only if s1s_1 satisfies the angle criterion:

∠G(s1)H(s1)=∑∠(s1−zj)−∑∠(s1−pi)=±(2q+1) 180∘\angle G(s_1)H(s_1) = \sum \angle(s_1 - z_j) - \sum \angle(s_1 - p_i) = \pm(2q+1)\,180^\circ

with q=0,1,2,…q = 0, 1, 2, \dots To apply it, draw vectors from all open-loop zeros and poles to s1s_1. Then take the sum of the zero angles minus the sum of the pole angles. If the result is an odd multiple of 180∘180^\circ, the point lies on the root locus for K>0K > 0; otherwise it does not. Example: for G=K/[s(s+2)]G = K/[s(s+2)], the point −1+j1-1 + j1 gives −(135∘+45∘)=−180∘-(135^\circ + 45^\circ) = -180^\circ, so it is on the locus.

✓ Answer checked by Claude Opus 5.5 (high effort)

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