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Criteria for a point to lie on root locus

Short answer

A point lies on the root locus if it satisfies the angle criterion: the sum of angles from zeros minus the sum from poles equals an odd multiple of 180°. Once on the locus, the magnitude criterion gives K = product of distances to poles divided by distances to zeros.

Discuss criteria for a point on s-plane that may lie on a root locus.

A point s1s_1 in the s-plane lies on the root locus only if it is a root of the characteristic equation 1+KG(s)H(s)=01 + KG(s)H(s) = 0 for some K≥0K \ge 0. Writing KG(s1)H(s1)=−1=1∠±180∘KG(s_1)H(s_1) = -1 = 1\angle \pm 180^\circ gives two criteria.

1. Angle criterion (decides whether the point is on the locus)

∠G(s1)H(s1)=∑j∠(s1−zj)−∑i∠(s1−pi)=±(2q+1) 180∘\angle G(s_1)H(s_1) = \sum_{j} \angle(s_1 - z_j) - \sum_{i} \angle(s_1 - p_i) = \pm(2q+1)\,180^\circ
  • Draw vectors from every open-loop pole and zero to s1s_1 and measure their angles from the positive real axis.
  • If (sum of zero angles) − (sum of pole angles) is an odd multiple of 180∘180^\circ, the point is on the locus. Otherwise it is not.
  • KK does not appear in this condition, so it alone fixes the shape of the locus.

2. Magnitude criterion (gives K at that point)

∣K G(s1)H(s1)∣=1  ⇒  K=∏i∣s1−pi∣∏j∣s1−zj∣|K\,G(s_1)H(s_1)| = 1 \;\Rightarrow\; K = \frac{\prod_i |s_1 - p_i|}{\prod_j |s_1 - z_j|}

That is, K is the product of the distances from the poles divided by the product of the distances from the zeros (1 if there are no zeros). This is used only after the angle criterion is satisfied.

Example

G(s)=Ks(s+4)G(s) = \dfrac{K}{s(s+4)}, test point s1=−2+j2s_1 = -2 + j2:

  • ∠s1=135∘\angle s_1 = 135^\circ and ∠(s1+4)=45∘\angle(s_1 + 4) = 45^\circ.
  • Sum =−(135∘+45∘)=−180∘= -(135^\circ + 45^\circ) = -180^\circ, so the point is on the locus.
  • K=∣s1∣ ∣s1+4∣=2.83×2.83=8K = |s_1|\,|s_1 + 4| = 2.83 \times 2.83 = 8.

Related real-axis rule

A real-axis point is on the locus if the number of real poles plus zeros to its right is odd. This rule follows directly from the angle criterion.

✓ Answer checked by Claude Opus 5.5 (high effort)

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