- 2080 Bhadra · 10 marks
Root locus with poles 0, −6, −2 ± j3
Short answer
Open-loop TF: K/[s(s+6)(s²+4s+13)]. Real-axis breakaway at s=-4.20 with K≈104.6. Departure angles from complex poles ∓70.6°. Stable for 0<K<227.8; at marginal K=227.8 it oscillates at 2.79 rad/s.
For a system having open loop pole-zero plot as in figure, sketch Root locus. [Figure: s-plane with open-loop poles at s = 0, s = −6 and s = −2 ± j3; no zeros]
Open-loop poles at and no zeros give
Characteristic equation: .
1. Branches
, : 4 branches, all ending at infinity.
2. Real-axis locus
Between and (one real pole to the right is an odd count). There is no locus left of −6.
3. Asymptotes
4. Breakaway point
Roots: and . Only is on the real-axis locus. Gain there:
5. Angle of departure from
Angles to : from : ; from : ; from : .
At , it is .
6. Imaginary-axis crossing
| Row | Col 1 | Col 2 | Col 3 |
|---|---|---|---|
| 1 | 37 | ||
| 10 | 78 | ||
| 29.2 | |||
. Auxiliary equation: rad/s.
Sketch
|
... | ....
.... | ....
.... x. .....
... .........X
... |
... |
.. |
----------x........*...................x----------
.. |
... |
... |
... .........X
.... x. .....
.... | ....
... | ....
|
-6 -4.2 -2 0
x pole * breakaway (-4.2)
X jw crossing (+-j2.79, K = 227.8)
The branches from and meet at and break away at ±90°, then bend to the ±135° asymptotes. The complex poles leave at , curve right, cross the -axis at and follow the ±45° asymptotes.
Answer: Breakaway at s = −4.20 (K ≈ 104.6). The departure angle is ∓70.6°. The system is stable for 0 < K < 227.8 and oscillates at 2.79 rad/s when K = 227.8.
✓ Answer checked by Claude Opus 5.5 (high effort)
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