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- 2071 Chaitra · 2+8 marks
- 2074 Chaitra · 2+8 marks
Map given poles and zeros, magnitude response
Short answer
Poles: 0.45±j0.77 (radius 0.89, inside unit circle) and -2±j0.3 (radius 2.02, outside); zeros: 1.2±j3 (radius 3.23). Magnitude response peaks near ω=π/3 (~7) from inner pole near unit circle, rises near ω=π from outer poles. Causal realization is unstable.
The poles of a system are located at 0.45+0.77i and −2±0.3i and zeroes at 1.2±3i. Map the poles and zero in the z-plane and plot the magnitude response of the system.
Reading: a real system has poles and zeros in complex-conjugate pairs. I read the poles as 0.45 ± 0.77i and −2 ± 0.3i, and the zeros as 1.2 ± 3i. No gain is given, so take K = 1:
H(z) = K (z − z₁)(z − z₁*) / [(z − p₁)(z − p₁*)(z − p₂)(z − p₂*)]
Locations (polar form)
| Point | Value | Radius | Angle |
|---|---|---|---|
| Pole p₁, p₁* | 0.45 ± 0.77i | 0.892 | ±59.7° |
| Pole p₂, p₂* | −2 ± 0.3i | 2.022 | ±171.5° |
| Zero z₁, z₁* | 1.2 ± 3i | 3.231 | ±68.2° |
Pole-zero map
^ Im
| o z1 = 1.2 + j3
|
.------|------.
x / | x \
----------+-------+-------+-----> Re
x \ | x /
'------|------'
|
| o z1* = 1.2 − j3
(x = pole, o = zero; the circle is the unit circle |z| = 1, crossing the Re axis at −1 and +1; the vertical scale is compressed.) The poles p₁, p₁* = 0.45 ± 0.77i are just inside the unit circle. The poles p₂, p₂* = −2 ± 0.3i (far left) and both zeros are outside it.
Magnitude response
|H(e^jω)| = |e^jω − z₁||e^jω − z₁*| / (product of the distances to the four poles), evaluated at points on the unit circle. Computed (K = 1):
| ω | 0 | π/6 | π/3 | π/2 | 2π/3 | 5π/6 | π |
|---|---|---|---|---|---|---|---|
| |H| | 1.11 | 1.57 | 7.04 | 2.09 | 2.09 | 3.36 | 4.71 |
7.04 | *
6.26 | *
5.48 | ***
4.69 | *** ***
3.91 | ***** ******
3.13 | ******* *********
2.35 | ************ **************
1.56 | **********************************
0.78 |*************************************
+-------------------------------------
0 pi/2 pi (w)
- A sharp peak (about 7.0) near ω ≈ π/3 (60°), because the pole 0.45 + 0.77i (radius 0.89) is very close to the unit circle at that angle.
- A smaller rise towards ω = π (about 4.7), caused by the poles at −2 ± 0.3i (angle about 171°); they are outside the circle but are nearest to it at ω ≈ π.
- The lowest value (≈ 1.1) is at ω = 0. The zeros (radius 3.2) are far from the circle, so they produce no notch.
Stability: the poles with |p| = 2.02 > 1 lie outside the unit circle, so a causal realisation is unstable. The magnitude response above exists only for the (non-causal) ROC that contains the unit circle.
✓ Answer checked by Claude Opus 5.5 (high effort)
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