- 2068 Shrawan · 4 marks
Poles and zeros of a network function
Short answer
Poles and zeros are the roots of denominator and numerator of the network function H(s). Poles determine the natural response terms (e.g., e^(p t)), stability, and damping; zeros set amplitudes and block specific frequencies. A pole-zero diagram on the s-plane directly reveals time-domain behavior.
What do you understand by poles and zeros of a network function? State their significance in analyzing the time domain response of a network.
A network function H(s) (driving point or transfer function) of a lumped linear network is a ratio of polynomials in the complex frequency s = σ + jω:
H(s) = N(s)/D(s) = K (s − z1)(s − z2)...(s − zm) / [(s − p1)(s − p2)...(s − pn)]
- Zeros z1, z2, ... are the values of s for which H(s) = 0 (roots of N(s)).
- Poles p1, p2, ... are the values of s for which H(s) → ∞ (roots of D(s)). They are also the natural frequencies of the network.
They are shown on the s-plane (poles as ×, zeros as ○) in a pole-zero diagram. Poles and zeros are either real or occur in complex-conjugate pairs.
Significance in the time domain
- Natural response. Each pole pi contributes a term Ki·e^(pi·t) to the response (partial fractions followed by the inverse Laplace transform). Example: H(s) = (s + 2)/[(s + 1)(s + 3)] = 0.5/(s + 1) + 0.5/(s + 3), so the impulse response is 0.5e^(−t) + 0.5e^(−3t).
- Stability. Poles in the left half plane (σ < 0) give decaying terms, so the network is stable. Poles on the jω axis give sustained oscillation (marginal stability). Poles in the right half plane give growing terms (unstable).
- Speed and damping. A real pole at −a gives e^(−at): the farther from the origin, the faster the decay. A complex pair −α ± jβ gives e^(−αt) cos(βt + θ): α sets the decay rate and β the oscillation frequency.
- Zeros do not create new time functions, but they set the amplitudes (residues Ki) and the phase of each term. A zero at s = z means that an input e^(zt) produces no output; a zero on the jω axis blocks that sinusoidal frequency completely.
- The forced response depends on the poles of the input as well; the poles of H(s) decide the transient (natural) part.
✓ Answer checked by Claude Opus 5.5 (high effort)
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