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Control system and why feedback makes response faster

Short answer

A control system regulates output to a desired value. Adding negative feedback reduces the time constant: for a first-order plant K/(τs+1), closed-loop time constant becomes τ/(1+K), so the response is (1+K) times faster, e.g., τ=1s, K=9 gives τ_cl=0.1s.

What is control system? "When feedback is added on a control system, its response is faster." Illustrate this statement mathematically.

Control system

A control system is an arrangement of components connected to command, direct or regulate a system so that the output reaches the desired value. When the output is measured and fed back to correct the input, it is a feedback (closed-loop) system.

Feedback makes the response faster

Take a first-order plant G(s)=Kτs+1G(s) = \dfrac{K}{\tau s + 1}.

Open loop: for a unit step input

c(t)=K(1−e−t/τ),time constant=τc(t) = K\left(1 - e^{-t/\tau}\right), \qquad \text{time constant} = \tau

Closed loop (unity feedback):

C(s)R(s)=G1+G=Kτs+1+K=K1+Kτ1+Ks+1\frac{C(s)}{R(s)} = \frac{G}{1+G} = \frac{K}{\tau s + 1 + K} = \frac{\dfrac{K}{1+K}}{\dfrac{\tau}{1+K}s + 1} c(t)=K1+K(1−e−t(1+K)/τ),τcl=τ1+Kc(t) = \frac{K}{1+K}\left(1 - e^{-t(1+K)/\tau}\right), \qquad \tau_{cl} = \frac{\tau}{1+K}

Comparing:

QuantityOpen loopClosed loop
Time constantτ\tauτ/(1+K)\tau/(1+K)
Settling time (2%)4τ4\tau4τ/(1+K)4\tau/(1+K)
Bandwidth1/τ1/\tau rad/s(1+K)/τ(1+K)/\tau rad/s
DC gainKKK/(1+K)K/(1+K)

The time constant is reduced by (1+K)(1+K), so the output reaches its final value (1+K)(1+K) times sooner.

Example: τ=1\tau = 1 s, K=9K = 9. Open loop: τ=1\tau = 1 s, settling time 4τ=44\tau = 4 s. Closed loop: τcl=1/10=0.1\tau_{cl} = 1/10 = 0.1 s, settling time =0.4= 0.4 s, i.e. ten times faster.

 c(t)
  |        .----------- closed loop (fast)
  |      /    ..------- open loop (slow)
  |     / .'
  |    /.'
  |   /'
  +-------------------------> t

(The curves are scaled to the same final value; in practice the reduced closed-loop gain is made up by a preamplifier.)

For a second-order system K/[s(s+a)]K/[s(s+a)] with unity feedback, ωn=K\omega_n = \sqrt{K} also rises with gain, so rise time and peak time fall. Hence adding feedback makes the response faster.

✓ Answer checked by Claude Opus 5.5 (high effort)

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