How are binary bits grouped for octal?

In 3s from the left without padding

Convert (10011)Gray to octal

Short answer

Gray code 10011 converts to binary 11101 (decimal 29) using B_MSB = G_MSB and B_i = B_i+1 XOR G_i. Binary 11101 grouped into 011 101 yields octal 35.

Convert (10011)Gray = (?)₈.

Convert Gray to binary, then group the binary in 3 bits for octal.

Step 1: Gray to binary ( $B_{MSB} = G_{MSB}$ , $B_i = B_{i+1} \oplus G_i$ )

$(10011)_{Gray} = (11101)_2 = 29_{10}$

Step 2: Binary to octal (group from the right: 011 101)

Group	011	101
Octal	3	5

Check: $3 \times 8 + 5 = 29$ .

Answer: $(10011)_{Gray} = (35)_8$

✓ Answer checked by Claude Opus 5.5 (high effort)