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Importance of Fermi energy in semiconductors
Short answer
Fermi level EF sets carrier concentrations (n = Nc exp[-(Ec-EF)/kT], p = Nv exp[-(EF-Ev)/kT]), indicates doping type (n-type near Ec, p-type near Ev), and is constant in equilibrium, determining band bending and built-in potentials. Applied voltage separates quasi-Fermi levels by eV.
Explain the importance of Fermi energy level in semiconductor.
The Fermi level is the energy at which the probability of occupation by an electron is exactly one half, from the Fermi-Dirac function
In a semiconductor it usually lies in the band gap, where there are no states, but it still fixes how many electrons and holes are present.
Importance
- Sets carrier concentrations. For a non-degenerate semiconductor:
The closer is to , the more electrons; the closer to , the more holes.
- Shows the type of semiconductor.
Intrinsic n-type p-type
--- Ec --- Ec --- Ec
... EF
... EF = EFi (near Ec)
(mid-gap) ... EF
--- Ev --- Ev --- Ev (near Ev)
- Intrinsic: near mid-gap, .
- n-type: , above mid-gap.
- p-type: , below mid-gap.
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Measures doping. The shift of from tells the doping level; heavy doping pushes into a band (degenerate semiconductor).
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Constant in equilibrium. In any system in thermal equilibrium, is the same everywhere. This rule gives band bending, the built-in potential of a pn junction ( before contact) and metal-semiconductor contact potentials.
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Applied voltage. An applied voltage separates the Fermi levels on the two sides by . means no net current; a gradient in drives current.
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Temperature behaviour. As rises, of an extrinsic semiconductor moves towards mid-gap, showing the change to intrinsic behaviour.
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Work function. fixes the work function , which decides contact behaviour (ohmic or Schottky).
✓ Answer checked by Claude Opus 5.5 (high effort)
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