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Loss tangent and dielectric power loss
Short answer
Loss tangent tan delta = epsilon_r'' / epsilon_r' quantifies dielectric loss. Power loss per unit volume is W_vol = omega epsilon_0 epsilon_r' E_rms^2 tan delta, showing it is proportional to angular frequency omega and tan delta.
What is loss tangent? Show that power loss in a dielectric material per unit volume is the function of frequency of the applied field and loss tangent.
Loss tangent
In an ideal dielectric the current leads the voltage by exactly 90°, so no power is lost. In a real dielectric, polarization cannot follow an AC field instantly, so part of the energy is turned into heat. This is described by a complex relative permittivity
where is the ordinary (storage) part and is the loss part. The loss tangent is
is the angle by which the current falls short of leading the voltage by 90°. Good insulators have (polyethylene); lossy ones are 0.01–0.1.
I_total
^ /
I_cap | /
(wC'V)| / delta
|/________> V
I_loss (wC''V)
Power loss per unit volume
Consider a parallel-plate capacitor with area , spacing , filled with the dielectric, and an applied voltage .
Capacitance with complex permittivity:
Current:
The term is in phase with and causes power loss; the term is the lossless capacitive current. So the dielectric acts like a capacitor with a parallel conductance
Power dissipated (using rms voltage ):
Divide by the volume and use :
Since :
Conclusion
The dielectric loss per unit volume is directly proportional to:
- the frequency of the applied field,
- the loss tangent (or loss factor ),
- the square of the field strength.
So insulation for high-frequency or high-voltage use (cables, RF capacitors) must have a very low . The same heating is used usefully in microwave ovens and dielectric heating of plastics and wood.
✓ Answer checked by Claude Opus 5.5 (high effort)
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