- 2067 Shrawan · 2+1 marks
Distortionless line and telephone lines
Short answer
A distortionless line has attenuation constant α and phase velocity independent of frequency, achieved when R/L = G/C. Telephone lines require this to preserve speech fidelity, ensuring all voice frequency components are equally attenuated and travel at the same speed, preventing signal distortion.
What is a distortionless transmission line? Why are telephone lines required to be distortionless?
Distortionless transmission line
A distortionless line is one whose attenuation is the same for all frequencies and whose phase velocity is also the same for all frequencies, so a signal of any shape reaches the end with only a reduction in amplitude, not a change in shape.
Condition (Heaviside): R/L = G/C, i.e. RC = LG.
Then γ = √[(R + jωL)(G + jωC)] = √(RG) + jω√(LC), so
α = √(RG) (independent of frequency)
β = ω√(LC) (linear in ω)
v = ω/β = 1/√(LC) (independent of frequency)
Z₀ = √(L/C) = √(R/G) (real, constant)
Why telephone lines must be distortionless
Speech contains many frequencies (about 300 Hz to 3.4 kHz). If α or v changed with frequency, the components would be attenuated unequally and would arrive at different times, so speech would sound muffled and unclear.
A telephone cable normally has high R, very small G and small L, so R/L ≫ G/C and the line is distorting. To make it distortionless, either L is increased (loading coils added at regular intervals, as Heaviside suggested) or G is increased (not preferred because it increases attenuation). Increasing L is the practical method, and gives a nearly constant α, v and Z₀ over the voice band.
✓ Answer checked by Claude Opus 5.5 (high effort)
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