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Short note: Distortionless transmission

Short answer

Distortionless transmission requires the output to be a scaled, delayed copy of the input, y(t)=K x(t−t_d). The channel must provide constant amplitude response |H(f)|=K and linear phase θ(f)=−2πf t_d, so all frequency components are equally amplified and have the same time delay t_d.

Write a short note on distortionless transmission.

Distortionless transmission means the output of a system (channel, filter or amplifier) has exactly the same shape as the input; only its amplitude may be scaled by a constant and it may be delayed by a fixed time:

y(t)=K x(t−td)y(t) = K\,x(t - t_d)

where KK is a constant gain and tdt_d a constant delay.

Transfer function: taking the Fourier transform,

Y(f)=KX(f) e−j2πftd  ⇒  H(f)=K e−j2πftdY(f) = K X(f)\,e^{-j2\pi f t_d} \;\Rightarrow\; H(f) = K\,e^{-j2\pi f t_d}

and the impulse response is h(t)=K δ(t−td)h(t) = K\,\delta(t - t_d).

Conditions (over the band occupied by the signal):

  1. Constant amplitude response: ∣H(f)∣=K|H(f)| = K. All frequency components are amplified or attenuated equally.
  2. Linear phase response: θ(f)=−2πftd\theta(f) = -2\pi f t_d (a straight line through the origin, or through ±nπ\pm n\pi). All components are delayed by the same time tdt_d; the group delay −12πdθdf=td-\frac{1}{2\pi}\frac{d\theta}{df} = t_d is constant.
 |H(f)|              theta(f)
   |                   |\
 K +-----------        | \  slope = -2*pi*td
   |                   |  \
   +-----------> f   --+---\------> f
                       |    \

Types of distortion when conditions fail:

  • Amplitude distortion: ∣H(f)∣|H(f)| not constant, so some frequencies are boosted or cut more than others.
  • Phase (delay) distortion: phase not linear, so components arrive at different times; serious for video and data pulses (causes ISI).
  • Non-linear distortion: the system is non-linear, creating harmonics and intermodulation products.

In practice exact distortionless transmission is impossible over all frequencies, but it is enough for ∣H(f)∣|H(f)| to be flat and the phase linear over the signal bandwidth. Equalizers are used to correct channel amplitude and phase response.

✓ Answer checked by Claude Opus 5.5 (high effort)

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