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Signum signal; distortionless transmission

Short answer

The signum function sgn(t) is +1 for t>0, 0 at t=0, -1 for t<0. Distortionless transmission means y(t)=K x(t-t_d), requiring H(f)=K e^{-j2π f t_d}: constant amplitude |H(f)|=K and linear phase θ(f)= -2π f t_d. This ensures no amplitude or phase distortion, preserving pulse shapes and signal quality.

Define signum signal. Explain the significance of distortionless transmission in communication system with its necessary derivation.

Signum signal

The signum (sign) function gives the sign of its argument:

sgn(t)={+1,t>00,t=0−1,t<0\text{sgn}(t) = \begin{cases} +1, & t > 0 \\ 0, & t = 0 \\ -1, & t < 0 \end{cases}

It is an odd function, related to the unit step by sgn(t)=2u(t)−1\text{sgn}(t) = 2u(t) - 1, and its Fourier transform is 1jπf\frac{1}{j\pi f}. It is used in defining the Hilbert transform: X^(f)=−j sgn(f)X(f)\hat X(f) = -j\,\text{sgn}(f)X(f).

Distortionless transmission: significance and derivation

In a communication system the receiver must get the same waveform that was sent; otherwise pulses overlap (ISI), speech/music lose quality and video gets smeared. Transmission is distortionless when the output is only a scaled, delayed copy of the input:

y(t)=K x(t−td)y(t) = K\,x(t - t_d)

Taking the Fourier transform (time-shift property):

Y(f)=K X(f) e−j2πftdH(f)=Y(f)X(f)=K e−j2πftd\begin{aligned} Y(f) &= K\,X(f)\,e^{-j2\pi ft_d} \\ H(f) &= \frac{Y(f)}{X(f)} = K\,e^{-j2\pi ft_d} \end{aligned}

So ∣H(f)∣=K|H(f)| = K and θ(f)=−2πftd\theta(f) = -2\pi ft_d, and h(t)=Kδ(t−td)h(t) = K\delta(t - t_d). The conditions are:

  1. Constant amplitude response over the signal band (no amplitude distortion).
  2. Linear phase response, i.e. constant delay tdt_d for all components (no phase distortion).
 |H(f)|               theta(f)
 K +-----------          |\
   |                     | \ slope -2*pi*td
 --+-----------> f     --+--\-------> f
                         |   \

Significance:

  • Gives the requirement for designing channels, amplifiers and filters: flat gain and linear phase over the signal bandwidth.
  • Explains amplitude distortion (non-flat gain) and phase/delay distortion (non-linear phase); the ear is not very sensitive to phase distortion, but video and digital data are.
  • Shows why equalizers are used in telephone lines, modems and TV to correct the channel.
  • Since an exact distortionless system is ideal, the conditions only need to hold over the bandwidth of the transmitted signal.

✓ Answer checked by Claude Opus 5.5 (high effort)

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