- 2067 Mangsir · 6 marks
Plane wave in free space, find β and H
Short answer
β = ω/c = 10⁷π/(3×10⁸) ≈ 0.105 rad/m. H = (E₀/η₀) cos(ωt−βz) a_y = (2/377) cos(10⁷πt−0.105z) a_y ≈ 5.31 cos(10⁷πt−0.105z) a_y mA/m.
A z-polarized uniform plane wave propagating in free space has E = 2 cos(10⁷πt − βz) a_x, determine β and H.
Given: E = 2 cos(10⁷πt − βz) a_x V/m in free space. The wave moves in +z with E along a_x (the question's "z-polarized" refers to travel along z).
Phase constant
ω = 10⁷π rad/s
β = ω/c = 10⁷π / (3×10⁸) = π/30
β ≈ 0.105 rad/m
(Frequency f = ω/2π = 5 MHz, λ = 2π/β = 60 m.)
Magnetic field
For a uniform plane wave, H = (1/η) a_k × E, and in free space η₀ = 120π ≈ 377 Ω. The direction of travel is a_z:
a_z × a_x = a_y
H = (E₀/η₀) cos(ωt − βz) a_y
= (2/377) cos(10⁷πt − 0.105z) a_y
= 5.31 cos(10⁷πt − 0.105z) a_y mA/m
Check: E × H = a_x × a_y = a_z, so power flows along +z, as it should.
Answer: β = 0.105 rad/m; H = 5.31 cos(10⁷πt − 0.105z) a_y mA/m.
✓ Answer checked by Claude Opus 5.5 (high effort)
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