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Plane wave in free space, find β and H

Short answer

β = ω/c = 10⁷π/(3×10⁸) ≈ 0.105 rad/m. H = (E₀/η₀) cos(ωt−βz) a_y = (2/377) cos(10⁷πt−0.105z) a_y ≈ 5.31 cos(10⁷πt−0.105z) a_y mA/m.

A z-polarized uniform plane wave propagating in free space has E = 2 cos(10⁷πt − βz) a_x, determine β and H.

Given: E = 2 cos(10⁷πt − βz) a_x V/m in free space. The wave moves in +z with E along a_x (the question's "z-polarized" refers to travel along z).

Phase constant

ω = 10⁷π rad/s
β = ω/c = 10⁷π / (3×10⁸) = π/30
β ≈ 0.105 rad/m

(Frequency f = ω/2π = 5 MHz, λ = 2π/β = 60 m.)

Magnetic field

For a uniform plane wave, H = (1/η) a_k × E, and in free space η₀ = 120π ≈ 377 Ω. The direction of travel is a_z:

a_z × a_x = a_y
H = (E₀/η₀) cos(ωt − βz) a_y
  = (2/377) cos(10⁷πt − 0.105z) a_y
  = 5.31 cos(10⁷πt − 0.105z) a_y   mA/m

Check: E × H = a_x × a_y = a_z, so power flows along +z, as it should.

Answer: β = 0.105 rad/m; H = 5.31 cos(10⁷πt − 0.105z) a_y mA/m.

✓ Answer checked by Claude Opus 5.5 (high effort)

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