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- 2077 Chaitra · 6 marks
Numerical: cordless phone free space path loss
Short answer
Free space path loss is found using PL(dB)=20 log(4πd/λ). With f=52 MHz, λ=c/f=5.769 m, d=50 m, PL = 20 log(108.91) = 40.7 dB.
Given a cordless phone operating at 52000 kHz frequency which has a range of 50 m. Determine the free space path loss.
Free space path loss (with unity gain antennas) is given by the Friis equation:
PL(dB) = 10 log(Pt/Pr) = 20 log(4πd/λ)
Given: f = 52 000 kHz = 52 MHz, d = 50 m (range of the phone).
Step 1: Wavelength
λ = c/f = 3×10⁸ / 52×10⁶ = 5.769 m
Step 2: Check far field
The phone's antenna is small (much less than λ), so the far field begins within a few wavelengths; 50 m is about 8.7λ, so the Friis equation can be used.
Step 3: Path loss
4πd/λ = 4π × 50 / 5.769 = 108.91
PL = 20 log(108.91) = 40.74 dB
Check using the practical form:
PL = 32.44 + 20 log f(MHz) + 20 log d(km)
= 32.44 + 20 log 52 + 20 log 0.05
= 32.44 + 34.32 − 26.02
= 40.74 dB
Answer: Free space path loss at the 50 m range ≈ 40.7 dB (the received power is about 1/11 860 of the transmitted power for unity-gain antennas).
✓ Answer checked by Claude Opus 5.5 (high effort)
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