- Asked 2/22
- 2080 Chaitra · 2+4 marks
Doppler effect; cordless phone path loss
Short answer
Doppler effect is the change in received frequency due to relative motion, with maximum shift fm = v/λ. For the cordless phone at 52 MHz and 50 m, free space path loss is 40.7 dB.
Define Doppler's effect in small scale fading. (i) Given a cordless phone operating at 52000 kHz frequency which has a range of 50 m. Determine the free space path loss.
Doppler effect in small-scale fading
The Doppler effect is the apparent change in the frequency of a received signal due to relative motion between transmitter and receiver. A mobile moving at speed v receives a wave arriving at angle θ to its direction of motion with a frequency shift
fd = (v/λ)·cosθ
In a multipath channel, waves arrive from many angles, so each has a different Doppler shift. The received spectrum spreads over fc ± fm (fm = v/λ). This Doppler spread causes random frequency modulation and makes the channel time-varying; it decides whether fading is fast or slow (through coherence time Tc ≈ 0.423/fm).
Free space path loss of the cordless phone
Given: f = 52 000 kHz = 52 MHz, d = 50 m. Assuming unity gain antennas:
λ = c/f = 3×10⁸ / 52×10⁶ = 5.769 m
PL = 20 log(4πd/λ)
= 20 log(4π × 50 / 5.769)
= 20 log(108.91)
= 40.74 dB
(check: 32.44 + 20 log 52 + 20 log 0.05
= 32.44 + 34.32 − 26.02 = 40.74 dB)
Answer: Free space path loss ≈ 40.7 dB.
✓ Answer checked by Claude Opus 5.5 (high effort)
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