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Wien-bridge oscillator working
Short answer
A Wien-bridge oscillator uses an op-amp with a positive feedback RC network that provides zero phase shift at f₀ = 1/(2πRC). To sustain oscillation, the non-inverting gain must be exactly 3, requiring Rf = 2R₁.
Explain the working principle of Wien-Bridge oscillator with circuit diagram and necessary expressions.
A Wien-bridge oscillator is an audio-frequency RC oscillator which uses an op-amp (non-inverting amplifier) with a Wien-bridge network as the positive-feedback path. It gives a low-distortion sine wave.
Circuit diagram
+-----[ Rf ]-----+
| |
+-----+-----(-)\ |
| >-----+------o Vo
| +-----(+)/ |
[R1] | |
| +---[R]---[C]----+ series arm: Vo to (+)
GND |
+---[R]--+
| |
+---[C]--+
|
GND parallel arm: (+) to ground
The series arm (R in series with C) joins Vo to the (+) input, and the parallel arm (R in parallel with C) joins the (+) input to ground. Rf and R1 form the gain-setting divider at the (−) input.
- Positive feedback: series R-C from the output to the (+) input, and parallel R-C from the (+) input to ground (the Wien network).
- Negative feedback: the divider Rf and R1 (sets the closed-loop gain).
Working and expressions
The feedback factor of the Wien network (with equal R and C) is
β = Vf/Vo = 1 / [3 + j(ωRC − 1/(ωRC))]
- At ω = ωo = 1/(RC): the reactive part is zero, so β = 1/3 and the phase shift is 0°.
- Barkhausen condition: the loop gain Aβ must be unity with 0° phase, so the amplifier gain must be
A = 1 + Rf/R1 = 3 → Rf = 2 R1
- Frequency of oscillation:
fo = 1 / (2π R C)
(If the arm values are unequal, with Ra and Ca in the series arm and Rb and Cb in the parallel arm: fo = 1/(2π √(Ra Rb Ca Cb)).)
To start the oscillation, the gain is made slightly above 3 (Rf slightly more than 2R1), and the amplitude is limited by a nonlinear element (a lamp or a diode network in the feedback). Example: R = 10 kΩ, C = 16 nF gives fo ≈ 1 kHz.
✓ Answer checked by Claude Opus 5.5 (high effort)
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