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Short note: Factor of safety

Short answer

Factor of safety (FS) is the ratio of resisting forces (shear strength) to driving forces (shear stress) on a slope. FS>1 indicates stability; typical design values are 1.3–1.5 for permanent slopes and 1.1–1.2 for temporary cuts. For a planar rock slide, FS = (cA+W cosψ tanφ)/(W sinψ) gave 1.61 for a 30° slope.

Write a short note on factor of safety.

Factor of safety (FS) is the ratio of the forces (or shear strength) resisting failure of a slope to the forces (or shear stress) driving it.

FS=Resisting force (shear strength)Driving force (shear stress)FS = \frac{\text{Resisting force (shear strength)}}{\text{Driving force (shear stress)}}
  • FS>1FS > 1: stable; FS=1FS = 1: limiting equilibrium; FS<1FS < 1: failure.
  • Usual design values are 1.3 to 1.5 for permanent slopes, and 1.1 to 1.2 for temporary cuts (higher when failure would be disastrous).
  • For a planar rock slide on a plane dipping at ψp\psi_p, with block weight WW, cohesion cc, area AA of the sliding plane and friction angle ϕ\phi:
FS=cA+Wcos⁡ψptan⁡ϕWsin⁡ψpFS = \frac{cA + W\cos\psi_p\tan\phi}{W\sin\psi_p}

Example: W=1000W = 1000 kN, ψp=30∘\psi_p = 30^\circ, ϕ=35∘\phi = 35^\circ, c=10c = 10 kPa, A=20A = 20 m2^2. Resisting =200+606.4=806.4= 200 + 606.4 = 806.4 kN; driving =500= 500 kN. Answer: FS=1.61FS = 1.61 (stable).

✓ Answer checked by Claude Opus 5.5 (high effort)

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