- 2075 Chaitra · 6 marks
BL, displacement and momentum thickness
Short answer
Boundary layer thickness δ is the distance at which u = 0.99U, defining the viscous region. Displacement thickness δ* = ∫ (1 − u/U) dy corrects the external flow area in ducts and wind tunnels. Momentum thickness θ = ∫ (u/U)(1 − u/U) dy is used in the momentum integral equation to find wall shear stress and drag force.
Explain concept of Boundary layer thickness. Displacement thickness and Momentum thickness with their applications each.
Boundary layer thickness ()
It is the distance from the wall, measured normal to it, at which the velocity reaches 99% of the free-stream velocity ().
Application: It marks out the region where viscous effects matter. It is used to fix the size of the region to be analysed, to place probes and decide the wall clearance in wind tunnels, and as the upper limit of the integrals that give and .
Displacement thickness ()
It is the distance by which the external flow is shifted away from the wall because of the velocity deficit in the boundary layer:
Application: In wind tunnels, diffusers and ducts the walls are moved outward (or the area is enlarged) by to keep the core velocity constant. It also gives the pressure change in a duct entrance, and the effective contour of an aerofoil or body for the outer potential flow.
Momentum thickness ()
It is the thickness of a fluid layer that, moving at velocity , carries the momentum lost because of the boundary layer:
Application: It is used in the momentum integral equation to find the wall shear stress and the drag force on a surface: , and for a plate of width ( taken at the trailing edge).
| Thickness | Measures loss of | Typical use |
|---|---|---|
| Extent of viscous region | Size of region | |
| Mass flow (discharge) | Area correction, outer flow | |
| Momentum | Drag, shear stress |
✓ Answer checked by Claude Opus 5.5 (high effort)
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