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Chapter 8 · 3 hours

Boundary Layer theory

IOE past exam questions

Past questions and answers

11 questions set from this chapter. Most repeated first.

  • 2079 Baisakh · 1+2+3 marks

What is boundary layer? Explain boundary layer thickness and displacement thickness. Compute the ratio of these quantities for the boundary layer described by the velocity distribution uU=(yδ)1/7\frac{u}{U} = \left(\frac{y}{\delta}\right)^{1/7}.

Answer

The ratio of displacement thickness to boundary layer thickness for the 1/7 power-law profile is δ∗/δ=1/8=0.125\delta^*/\delta = 1/8 = 0.125.

Boundary layer

When a real fluid flows past a solid surface, the fluid layer touching the surface sticks to it (no-slip). Velocity rises from zero at the wall to the free-stream velocity UU over a thin region near the surface. This thin region, where viscous shear is important, is the boundary layer. Outside it the flow behaves as an ideal (inviscid) fluid.

Boundary layer thickness (δ\delta)

It is the distance from the wall at which the velocity reaches 99% of the free-stream velocity: u=0.99 Uu = 0.99\,U at y=δy = \delta.

Displacement thickness (δ∗\delta^*)

It is the distance by which the external streamlines are shifted away from the wall because of the slow-moving fluid in the boundary layer. Equivalently, it is the thickness of a layer of free-stream flow that has the same discharge as the loss of discharge caused by the boundary layer.

δ∗=∫0δ(1−uU)dy\delta^* = \int_0^{\delta}\left(1 - \frac{u}{U}\right)dy

Ratio for u/U=(y/δ)1/7u/U = (y/\delta)^{1/7}

δ∗=∫0δ[1−(yδ)1/7]dy=δ−δ1+1/7=δ−78δ=δ8\begin{aligned} \delta^* &= \int_0^{\delta}\left[1 - \left(\frac y\delta\right)^{1/7}\right]dy = \delta - \frac{\delta}{1 + 1/7}\\ &= \delta - \frac{7}{8}\delta = \frac{\delta}{8} \end{aligned} δ∗δ=18=0.125\frac{\delta^*}{\delta} = \frac18 = 0.125

Answer: δ∗/δ=1/8\delta^*/\delta = 1/8, so the displacement thickness is 12.5% of the boundary layer thickness.

  • 2078 Bhadra · 6 marks

Air flows in the entrance region of a square duct, as shown. The velocity is uniform, U0U_0 = 30 m/s, and the duct is 76 mm square. At a section 0.3 m downstream from the entrance, the displacement thickness on each wall measures 0.9 mm. Determine pressure change between section 1 and 2. [Figure: duct entrance, uniform velocity U0U_0 at section 1, section 2 with δ2\delta_2 = 0.9 mm; square cross-section 76 mm by 76 mm]

Answer

Outside the boundary layers the core flow is accelerated, because the displacement thickness reduces the effective flow area. Apply continuity to the core, then Bernoulli. The pressure falls by about 55.7 Pa.

Assumptions

Air density ρ=1.23 kg/m3\rho = 1.23\ \text{kg/m}^3. The flow in the core is frictionless and incompressible, so Bernoulli applies between sections 1 and 2.

  Section 1                  Section 2
  ----------------------     ----------------------
   U0 = 30 m/s uniform  -->    core U2 (faster)
  ----------------------     = boundary layer (d* = 0.9 mm)

Continuity (effective area)

At section 2 the effective flow area is reduced by δ∗\delta^* on each wall:

Aeff=(76−2×0.9)2=74.22 mm2,A1=762 mm2A_{eff} = (76 - 2 \times 0.9)^2 = 74.2^2\ \text{mm}^2,\qquad A_1 = 76^2\ \text{mm}^2 U0A1=U2Aeff  ⇒  U2=30(7674.2)2=31.47 m/sU_0A_1 = U_2A_{eff} \;\Rightarrow\; U_2 = 30\left(\frac{76}{74.2}\right)^2 = 31.47\ \text{m/s}

Bernoulli (horizontal duct)

p1−p2=12ρ (U22−U02)=12(1.23)(31.472−302)=55.7 Pa\begin{aligned} p_1 - p_2 &= \tfrac12\rho\,(U_2^2 - U_0^2) \\ &= \tfrac12(1.23)(31.47^2 - 30^2) = 55.7\ \text{Pa} \end{aligned}

Answer: p2−p1=−55.7p_2 - p_1 = -55.7 Pa, i.e. the pressure drops by about 55.7 Pa (about 5.7 mm of water) between sections 1 and 2.

  • 2078 Bhadra · 2+2 marks

What is laminar Sub-layer? Differentiate between the characteristics of laminar and turbulent boundary layer.

Answer

Laminar sub-layer

In a turbulent boundary layer, a very thin layer next to the solid surface still has laminar flow, because the wall damps out the eddies there. In this layer the velocity changes almost linearly with yy and the shear is purely viscous, τ0=μ (du/dy)\tau_0 = \mu\,(du/dy). Its thickness is

δ′=11.6 νu∗,u∗=τ0/ρ\delta' = \frac{11.6\,\nu}{u_*},\qquad u_* = \sqrt{\tau_0/\rho}

It is only a small fraction of the total boundary layer thickness, but it controls wall shear and heat transfer, and decides whether a surface is hydraulically smooth or rough.

Laminar vs turbulent boundary layer

PointLaminar BLTurbulent BL
FlowSmooth, orderly layersRandom eddies and mixing
WhereNear leading edge, Rex<5×105Re_x < 5\times10^5Downstream, Rex>5×105Re_x > 5\times10^5
Shear stress sourceViscosity onlyViscosity plus turbulent (Reynolds) stress
Velocity profileParabolic type, gradualFuller, steeper at wall (≈1/7\approx 1/7 power law)
Thicknessδ=5x/Rex\delta = 5x/\sqrt{Re_x}, grows slowlyδ=0.37x/Rex0.2\delta = 0.37x/Re_x^{0.2}, grows faster
Wall shearLowerHigher
SeparationSeparates easily under adverse pressure gradientResists separation better
  • 2078 Kartik · 7 marks

Explain the development of boundary layer along a thin flat plate held parallel to uniform flow. Also point out the salient features.

Answer

When a uniform stream of velocity UU flows parallel to a thin flat plate, the fluid at the surface sticks to it (no-slip). Viscous shear slows the layers above, and a region of velocity gradient grows along the plate. This is the boundary layer. Its thickness δ\delta increases with distance xx from the leading edge.

Development

 U ->  free stream (inviscid)
 ---------------------------------------------------
        .---- laminar ----.transition.---- turbulent ---
 U -> ----------___________......_____________________
                   boundary layer   (laminar sub-layer
 =================================   at wall)
 leading edge         x_cr        flat plate -->
  1. Laminar zone: Starting at the leading edge, the layer is thin and the flow is orderly, in smooth layers. Thickness grows as δ∝x\delta \propto \sqrt{x} (Blasius, δ=5x/Rex\delta = 5x/\sqrt{Re_x}).
  2. Transition zone: At a critical Reynolds number Rex,cr≈5×105Re_{x,cr} \approx 5\times10^5 (for a smooth plate and low free-stream turbulence), disturbances amplify and the flow starts to change to turbulent.
  3. Turbulent zone: Beyond transition, mixing by eddies makes the layer thicker (δ∝x0.8\delta \propto x^{0.8}) with a fuller velocity profile. A very thin laminar sub-layer remains next to the wall.

where Rex=Ux/νRe_x = Ux/\nu.

Salient features

  • Velocity is zero at the wall and reaches 0.99U0.99U at y=δy = \delta.
  • δ\delta increases downstream; the pressure gradient along a flat plate is zero.
  • Wall shear stress is highest near the leading edge in the laminar region, drops, then jumps at transition and is higher in the turbulent region than for laminar flow at the same xx.
  • A larger viscosity or lower velocity (lower ReRe) gives a thicker layer.
  • Pressure across the layer is nearly constant, ∂p/∂y≈0\partial p/\partial y \approx 0.
  • The effect of the plate on the flow outside the boundary layer is represented by the displacement thickness δ∗\delta^*.
  • 2076 Chaitra · 4 marks

Flow takes place over a flat plate exposed parallel to free stream. Mention characteristics of flow and draw a neat sketch of the boundary layer development showing, (i) Laminar boundary layer, (ii) Turbulent boundary layer, (iii) Transition zone, (iv) Laminar sub layer. What is displacement thickness?

Answer

Characteristics of the flow

A flat plate held parallel to a free stream develops a boundary layer, in which viscosity slows the fluid near the surface. Velocity is zero at the wall and equals the free-stream velocity UU at the edge of the layer (y=δy = \delta). The thickness δ\delta grows with distance xx. The flow is laminar near the leading edge, changes through a transition region and becomes turbulent downstream, with the change at about Rex=Ux/ν≈5×105Re_x = Ux/\nu \approx 5\times10^5. Outside the layer the flow is practically inviscid.

Sketch

 U ->
 ---------------------------------------------------
                                      Turbulent BL
          Laminar BL    Transition  _________________
 U -> ----------____________......___________________
                                      ..... laminar sub-layer
 ========================================= plate
 leading edge      x ------------------------>
   (i) laminar  (iii) transition  (ii) turbulent
   (iv) laminar sub-layer: thin film at the wall
  • (i) Laminar boundary layer: smooth flow, δ=5x/Rex\delta = 5x/\sqrt{Re_x}.
  • (iii) Transition zone: flow changes from laminar to turbulent, Rex≈3×105Re_x \approx 3\times10^5 to 5×1055\times10^5 or more.
  • (ii) Turbulent boundary layer: eddy mixing, thicker, fuller velocity profile.
  • (iv) Laminar sub-layer: very thin viscous layer next to the wall, even under the turbulent layer.

Displacement thickness

It is the distance by which the outer streamlines are displaced away from the plate because of the reduction of flow in the boundary layer:

δ∗=∫0δ(1−uU)dy\delta^* = \int_0^{\delta}\left(1 - \frac uU\right)dy
  • 2076 Asoj · 2+2+4 marks

Air flows over a flat plate 2 m long and 1.5 m wide at a velocity of 6.5 m/s. Determine the shear stress, and displacement thickness at distance of 1.8 m from the leading edge. Also determine the drag force on the face of the plate.

Answer

Find the Reynolds number first to decide whether the boundary layer is laminar or turbulent, then use the matching formulas.

Assumptions

Air at about 20 °C: ρ=1.2 kg/m3\rho = 1.2\ \text{kg/m}^3, ν=1.5×10−5 m2/s\nu = 1.5\times10^{-5}\ \text{m}^2/\text{s}. U=6.5U = 6.5 m/s, L=2L = 2 m, B=1.5B = 1.5 m, x=1.8x = 1.8 m.

Reynolds numbers

Rex=Uxν=6.5(1.8)1.5×10−5=7.8×105,ReL=6.5(2)1.5×10−5=8.67×105Re_x = \frac{Ux}{\nu} = \frac{6.5(1.8)}{1.5\times10^{-5}} = 7.8\times10^5,\qquad Re_L = \frac{6.5(2)}{1.5\times10^{-5}} = 8.67\times10^5

Both exceed the critical value 5×1055\times10^5, so the boundary layer is taken as turbulent (1/7 power law, valid for Re<107Re < 10^7).

Boundary layer thickness and displacement thickness at x = 1.8 m

δ=0.37 xRex0.2=0.37(1.8)(7.8×105)0.2=0.0442 mδ∗=δ8=0.00552 m=5.52 mm\begin{aligned} \delta &= \frac{0.37\,x}{Re_x^{0.2}} = \frac{0.37(1.8)}{(7.8\times10^5)^{0.2}} = 0.0442\ \text{m} \\ \delta^* &= \frac{\delta}{8} = 0.00552\ \text{m} = 5.52\ \text{mm} \end{aligned}

Shear stress at x = 1.8 m

Cf=0.0576Rex0.2=0.003819τ0=Cf⋅12ρU2=0.003819(0.5)(1.2)(6.5)2=0.0968 N/m2\begin{aligned} C_f &= \frac{0.0576}{Re_x^{0.2}} = 0.003819 \\ \tau_0 &= C_f\cdot\tfrac12\rho U^2 = 0.003819(0.5)(1.2)(6.5)^2 = 0.0968\ \text{N/m}^2 \end{aligned}

Drag force on one face

CD=0.074ReL0.2=0.004805FD=CD⋅12ρU2 (LB)=0.004805(0.5)(1.2)(6.5)2(2×1.5)=0.365 N\begin{aligned} C_D &= \frac{0.074}{Re_L^{0.2}} = 0.004805 \\ F_D &= C_D\cdot\tfrac12\rho U^2\,(L B) = 0.004805(0.5)(1.2)(6.5)^2(2\times1.5) = 0.365\ \text{N} \end{aligned}

If the laminar length at the leading edge is allowed for, CD=0.074/ReL0.2−1700/ReL=0.002843C_D = 0.074/Re_L^{0.2} - 1700/Re_L = 0.002843 and FD=0.216F_D = 0.216 N.

Answer: τ0≈0.097\tau_0 \approx 0.097 N/m², δ∗≈5.5\delta^* \approx 5.5 mm, drag on one face ≈0.37\approx 0.37 N (about 0.22 N if the initial laminar part is included).

  • 2075 Chaitra · 6 marks

Explain concept of Boundary layer thickness. Displacement thickness and Momentum thickness with their applications each.

Answer

Boundary layer thickness (δ\delta)

It is the distance from the wall, measured normal to it, at which the velocity reaches 99% of the free-stream velocity UU (u=0.99Uu = 0.99U).

Application: It decides the region where viscous effects matter, so it is used to fix the size of the region to be analysed, to design the spacing of probes and the wall clearance in wind tunnels, and to size the thickness of insulation or coatings in flow.

Displacement thickness (δ∗\delta^*)

It is the distance by which the external flow is shifted away from the wall because of the velocity deficit in the boundary layer:

δ∗=∫0δ(1−uU)dy\delta^* = \int_0^{\delta}\left(1 - \frac uU\right)dy

Application: In wind tunnels, diffusers and ducts the walls are placed (or the area is enlarged) by δ∗\delta^* to keep the core velocity constant. It also gives the pressure change in the duct entrance, and the real contour of an aerofoil or body for the outside potential flow.

Momentum thickness (θ\theta)

It is the thickness of fluid layer that, at velocity UU, carries the momentum lost because of the boundary layer:

θ=∫0δuU(1−uU)dy\theta = \int_0^{\delta}\frac uU\left(1 - \frac uU\right)dy

Application: It is used in the momentum integral equation to find the wall shear stress and the drag force on a surface, τ0=ρU2 dθ/dx\tau_0 = \rho U^2\,d\theta/dx, and FD=ρU2θ bF_D = \rho U^2\theta\,b for a plate of width bb.

ThicknessMeasures loss ofTypical use
δ\deltaExtent of viscous regionSize of region
δ∗\delta^*Mass flow (discharge)Area correction, outer flow
θ\thetaMomentumDrag, shear stress
  • 2075 Asoj · 3 marks

Define boundary layer separation and stagnation point with the help of figure.

Answer

Boundary layer separation

When flow moves into a region of rising pressure (an adverse pressure gradient, dp/dx>0dp/dx > 0, as on the rear of a cylinder or in a diverging channel), the fluid near the wall loses momentum to friction and cannot go further. The velocity gradient at the wall becomes zero, (du/dy)y=0=0(du/dy)_{y=0} = 0. Beyond this point of separation, the flow near the wall reverses, the boundary layer leaves the surface and a wake of eddies forms.

 free stream ->  ___________________
                 \  boundary layer   separated flow
 body surface ====\=======S==========  S = separation point
                    --> <-- back flow    (du/dy = 0 at wall)

Separation causes high pressure (form) drag and, on a wing, loss of lift (stall).

Stagnation point

It is the point on the surface of a body in a flowing fluid where the fluid velocity becomes zero. The streamline dividing the flow splits here, and the pressure reaches its maximum value (stagnation pressure):

p0=p+12ρV2p_0 = p + \tfrac12\rho V^2
   ---->  ---->  ___
   ---->  ---->  /  |  stagnation point
   ---->  ----> (*  |  at the nose, v = 0
  • 2074 Asoj · 5 marks

Define boundary layer concept. Explain the terms boundary layer thickness, laminar sub-layer and point of separation of boundary layer with sketch.

Answer

Boundary layer concept

When a real fluid flows past a solid body, fluid at the surface sticks to it (no-slip). Velocity increases from zero at the wall to the free-stream velocity UU over a thin layer. Viscous shear is large only within this layer, called the boundary layer. Outside it the flow is treated as ideal (potential) flow. This idea (Prandtl, 1904) lets the flow be split into a thin viscous layer and an outer inviscid region.

Boundary layer thickness (δ\delta)

It is the distance from the wall at which the velocity equals 99% of the free-stream velocity: u=0.99Uu = 0.99U at y=δy = \delta.

Laminar sub-layer

Under a turbulent boundary layer there is a very thin layer next to the wall in which flow stays laminar and the shear is purely viscous: τ0=μ du/dy\tau_0 = \mu\,du/dy. Its thickness is δ′=11.6ν/u∗\delta' = 11.6\nu/u_*.

Point of separation

It is the point on the surface where flow moving against an adverse pressure gradient (dp/dx>0dp/dx > 0) is brought to rest at the wall, so (du/dy)y=0=0(du/dy)_{y=0} = 0. Downstream the flow near the wall reverses and the boundary layer leaves the surface, forming a wake.

 U -> ===========================
            turbulent BL         separation
                      ~~~~~~~~~~~~  S
 solid ========================\===\====
      laminar sub-layer        <-- back flow
  • 2073 Shrawan · 1+3+1 marks

Define the concept of boundary layer. Explain the growth of boundary layer in a close conduit (pipe flow). Give three examples of use of boundary layer concept.

Answer

Concept of boundary layer

The boundary layer is the thin layer next to a solid surface in which the fluid velocity changes from zero (at the wall, no-slip) to nearly the free-stream value. Viscous effects are confined to this layer; outside it the flow is inviscid.

Growth in a closed conduit (pipe flow)

 inlet            entrance length Le          fully developed
  ---------------------------------------------------------
   U0 ->  boundary layers grow     core meets   parabolic /
   uniform    from wall inward ->  at centre    turbulent profile
  ---------------------------------------------------------
  1. At the pipe entrance the velocity is nearly uniform, U0U_0. A boundary layer begins to grow from the wall at the entrance.
  2. The layer thickens along the pipe, slowing the fluid near the wall. By continuity the core fluid, outside the layer, accelerates, and the pressure drops faster than in fully developed flow.
  3. At a distance called the entrance (inlet) length LeL_e, the layers from the opposite walls meet at the centre. After this the velocity profile no longer changes with xx, and the flow is fully developed.
  4. Entrance length: laminar flow Le≈0.05 Re DL_e \approx 0.05\,Re\,D; turbulent flow Le≈4.4 Re1/6DL_e \approx 4.4\,Re^{1/6}D (about 25 to 40 diameters).

Three examples of use of the boundary layer concept

  1. Calculation of skin friction drag on ships, aircraft wings and plates.
  2. Explaining separation and stall on aerofoils, and the design of streamlined bodies to reduce form drag.
  3. Design of wind tunnels, diffusers and ducts (allowing for displacement thickness), and prediction of the heat transfer from surfaces.
  • 2072 Chaitra · 1+3+1 marks

Define the concept of boundary layer. Explain the growth of boundary layer along a thin plate, when liquid is flowing over it, both for laminar and turbulent flow. Give two examples of use of boundary layer concept.

Answer

Concept of boundary layer

The boundary layer is the thin region next to a solid surface where the velocity changes from zero at the surface (no-slip) to the free-stream value UU, because of viscosity. Outside it the flow is effectively inviscid.

Growth along a thin plate

 U ->   ------------------------------------------
        laminar         transition      turbulent
 ------------___________.........______________________
   delta ~ sqrt(x)                        delta ~ x^0.8
 ========================================= plate -->
 leading edge

Laminar flow (near the leading edge, Rex<5×105Re_x < 5\times10^5)

  • The layer starts with zero thickness at the leading edge and grows slowly as viscous effects spread outward.
  • The fluid moves in smooth layers. Blasius's result: δ=5xRex\delta = \dfrac{5x}{\sqrt{Re_x}}, so δ∝x\delta \propto \sqrt{x}.
  • The velocity profile is nearly parabolic, with a gentle gradient at the wall.

Turbulent flow (downstream, Rex>5×105Re_x > 5\times10^5)

  • After a transition region the flow becomes turbulent and eddies mix the fluid strongly.
  • The layer is thicker and grows faster: δ=0.37xRex1/5\delta = \dfrac{0.37x}{Re_x^{1/5}}, δ∝x0.8\delta \propto x^{0.8}.
  • The profile is fuller (u/U=(y/δ)1/7u/U = (y/\delta)^{1/7}), the wall shear stress is larger, and a thin laminar sub-layer stays at the wall.

Here Rex=Ux/νRe_x = Ux/\nu.

Two examples of use

  1. Finding the skin-friction drag on ship hulls, aircraft wings and flat surfaces.
  2. Designing streamlined shapes to delay separation and reduce drag, and wind tunnel sections using displacement thickness.

Questions from Old Question Collection (CE 505) (IOE Fluid Mechanics (CE 505) exam papers from 2072 to 2079). Answers are written for this site; check them against your class notes.

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