Chapter 11 · 2 hours
Applications
IOE past exam questions
Past questions and answers
5 questions set from this chapter, 3 of them more than once. Most asked first.
- Asked 14 times
- 2082 Baisakh · 4 marks
- 2081 Baisakh · 4 marks
- 2081 Baisakh · 5 marks
- 2080 Bhadra · 5 marks
- 2080 Baisakh · 6 marks
- 2079 Bhadra · 4 marks
- 2078 Bhadra · 5 marks
- 2076 Chaitra · 4 marks
- 2076 Asoj · 5 marks
- 2075 Chaitra · 4 marks
- 2074 Chaitra · 4 marks
- 2073 Shrawan · 8 marks
- 2070 Chaitra · 5 marks
- 2069 Chaitra · 4 marks
- 2068 Chaitra · 4 marks
With the help of block diagram explain the operation of frequency counter.
Answer
A frequency counter measures the frequency of a signal by counting the number of its cycles during an accurately known time interval (the gate time) and displaying the count:
Block diagram
Input +-----------+ pulses +-----+ +-----------+
signal->| Amplifier |--------->| |-->| Decade |
| & Schmitt | | AND | | counters |
| trigger | +---->|gate | | (BCD) |
+-----------+ | +-----+ +-----+-----+
| |
+---------+ +---------+ | gate +----------v----+
| Crystal |->| Divider |-+ pulse | Latch |
| osc. | | chain |---+ +-------+-------+
+---------+ +---------+ | |
+----v-----+ +-------v-------+
| Control | | BCD to 7-seg |
| (reset, | | decoders and |
| latch) | | displays |
+----------+ +---------------+
Working of each block
- Amplifier and Schmitt trigger (wave shaper): amplifies the unknown input (sine, triangle, etc.) and converts it into clean rectangular pulses of the same frequency, one pulse per cycle.
- Time base: a crystal oscillator (e.g. 1 MHz) followed by a chain of divide-by-10 counters gives a very accurate gate pulse of 1 s, 0.1 s, 10 ms, … selected by the range switch.
- AND (main) gate: one input receives the shaped pulses, the other the gate pulse. Pulses pass to the counter only while the gate pulse is HIGH, i.e. for exactly .
- Decade counters: cascaded BCD counters (e.g. 7490) count the pulses that pass the gate; each counter is one decimal digit.
- Control logic: before each gate period it resets the counters; when the gate closes it sends a latch (transfer) pulse, then resets again for the next measurement.
- Latch, decoder and display: the latch holds the final count so the display does not flicker while counting; BCD-to-7-segment decoders (e.g. 7447) drive the LED displays.
Example
With s, if 5000 pulses pass the gate, Hz = 5 kHz. With a 0.1 s gate the same signal gives 500 counts, displayed as 5.00 kHz with the decimal point shifted. A longer gate gives better resolution (1 Hz for a 1 s gate); the accuracy depends on the crystal time base, with an error of ±1 count.
- Asked 5 times
- 2081 Bhadra · 5 marks
- 2080 Bhadra · 4 marks
- 2080 Baisakh · 4 marks
- 2079 Bhadra · 5 marks
- 2078 Kartik · 5 marks
Explain the concept of the multiplexing display. Illustrate with a suitable diagram to support your explanation.
Answer
A multiplexed display drives several 7-segment digits by sharing one set of segment lines (a–g) and one BCD-to-7-segment decoder among all digits, and switching the digits on one at a time in rapid sequence. Because each digit is refreshed faster than the eye can follow (persistence of vision), all digits appear to be lit continuously.
Need for multiplexing
- A non-multiplexed 4-digit display needs 4 decoders and segment lines.
- A multiplexed display needs only 1 decoder, 7 segment lines and 4 digit-select lines (11 lines in total).
- Fewer ICs, less wiring, lower power (only one digit draws current at a time).
Block diagram
BCD digit 0 ─┐
BCD digit 1 ─┤ 4-bit BCD BCD-to-7 a..g
BCD digit 2 ─┤ 4:1 MUX ────> segment ─────┬──┬──┬──┐
BCD digit 3 ─┘ (x4) decoder │ │ │ │
^ [D3][D2][D1][D0]
│ S1 S0 ^ ^ ^ ^
Clock ─> 2-bit ──┴──> 2-to-4 decoder ─────┴───┴───┴───┘
(~1 kHz) counter (one digit enabled at a time)
The segment lines a–g of all four displays are wired in parallel. Each display's common cathode (or common anode) is driven separately through a transistor by one output of the 2-to-4 decoder.
Operation
- A clock (typically 100 Hz – 1 kHz) drives a 2-bit counter that cycles 00, 01, 10, 11.
- The counter output selects one BCD digit through the data multiplexer and sends it to the single BCD-to-7-segment decoder.
- The same counter output goes to a 2-to-4 decoder, which enables only the matching display (e.g. count 00 turns on D0).
- So during the first time slot, digit 0's code appears on the segment lines and only D0 glows; in the next slot digit 1's code appears and only D1 glows, and so on.
- Each digit is ON for 1/4 of the cycle (duty cycle 25%). If the full scan repeats at more than about 50 times per second, no flicker is seen.
- Since each digit is ON only part of the time, a higher peak current is given to keep the brightness the same.
Example
To show 2025: in slot 0 the code for 5 is sent and D0 lights; slot 1 sends 2 to D1; slot 2 sends 0 to D2; slot 3 sends 2 to D3. Scanning at 1 kHz gives each digit 250 refreshes per second, so the eye sees "2025" steadily.
Multiplexed displays are used in digital clocks, frequency counters, calculators and digital meters.
- Asked 4 times
- 2081 Bhadra · 5 marks
- 2079 Baisakh · 6 marks
- 2075 Chaitra · 6 marks
- 2075 Asoj · 4 marks
With the help of block diagram explain the operation of time measurement circuit.
Answer
A time measurement circuit (digital timer / period meter) measures the time interval between two events by counting pulses of a known, accurate clock during that interval. If a clock of period gives counts, the measured time is .
Block diagram
Start ──> ┌──────┐
│ S-R │ Q = gate
Stop ──> │ FF │─────────┐
└──────┘ v
Crystal ─> Time-base ─> ┌─────┐
oscillator divider │ AND │
└──┬──┘
v
Reset ─────────────> ┌──────────────┐
│Decade counter│
└──────┬───────┘
v
┌──────────────┐
│ Latch │
└──────┬───────┘
v
┌──────────────┐
│BCD-to-7-seg │
│dec. + display│
└──────────────┘
Blocks
- Crystal oscillator – generates a very stable frequency (e.g. 1 MHz).
- Time-base divider – chain of decade counters (÷10 stages) giving selectable clock periods such as 1 µs, 10 µs, 1 ms. This sets the resolution of the reading.
- Start/stop control (S-R flip-flop) – the start pulse sets the flip-flop (); the stop pulse resets it (). So is HIGH exactly for the time interval to be measured.
- AND gate (main gate) – passes time-base clock pulses to the counter only while .
- Decade (BCD) counters – count the pulses passed by the gate.
- Latch, decoder and display – the latch holds the final count; BCD-to-7-segment decoders show it on the display (usually multiplexed).
Operation
- Before measurement the counters are reset to zero.
- The start event sets the flip-flop, opening the AND gate. Clock pulses enter the counter.
- The stop event resets the flip-flop, closing the gate. Counting stops.
- The count is latched and displayed; the time is , so the display reads directly in µs or ms depending on the selected time base.
Example
With a 1 ms time base, if 2,350 pulses pass the gate, then
Period measurement
For measuring the period of a signal, the input is shaped into pulses and applied to a toggle (divide-by-2) flip-flop; its output stays HIGH for exactly one period and acts as the gate. The accuracy is count plus the accuracy of the crystal.
- 2082 Shrawan · 2+5 marks
What is a BCD-to 7 segment display decoder? Explain the frequency counter with necessary diagrams.
Answer
BCD-to-7-segment decoder
A BCD-to-7-segment decoder is a combinational circuit that converts a 4-bit BCD input (DCBA = 0000 to 1001) into the seven outputs a–g needed to light the segments of a 7-segment display, so that the decimal digit 0–9 appears. Example: input 0101 (5) makes segments a, f, g, c, d active. The 7447 (active-LOW outputs, for common-anode displays) and 7448 (active-HIGH, for common-cathode) are common ICs.
a
─────
f | | b DCBA ─> [7447] ─> a b c d e f g
| g |
─────
e | | c
| |
─────
d
Frequency counter
A frequency counter measures the frequency of a signal by counting how many cycles of the signal occur during an accurately known gate time. If cycles are counted in gate time :
With s, the count is directly the frequency in Hz.
Input ─> Amplifier + Schmitt ──────┐
v
Crystal ─> Time-base ─> Gate ─> ┌─────┐
osc. divider control │ AND │
│ │ └──┬──┘
│ │ v
│ └─> Decade counters
│ reset │
│ v
└──────> Latch (strobe)
v
BCD-to-7-seg decoders
v
7-segment display
Blocks and operation
- Input shaper – an amplifier and Schmitt trigger convert the unknown input (sine, triangle, etc.) into clean rectangular pulses, one per cycle.
- Crystal oscillator and time-base divider – a stable oscillator (e.g. 1 MHz) is divided by decade counters to give accurate gate times such as 1 s, 0.1 s or 10 ms.
- Gate control flip-flop – produces a gate pulse of exactly width.
- Main AND gate – passes input pulses to the counters only during .
- Decade counters (e.g. 7490) – count the pulses in BCD.
- Latch – at the end of the gate time a strobe pulse copies the count into the latch so the display stays steady; then a reset pulse clears the counters for the next measurement.
- BCD-to-7-segment decoders and display – show the latched count, usually as a multiplexed display.
Example: with s, if 4,567 pulses are counted, Hz kHz.
A longer gate time gives better resolution ( count Hz) but a slower update.
- 2076 Chaitra · 1+4 marks
What are the applications of digital devices? Explain frequency counter.
Answer
Applications of digital devices
Digital ICs (gates, flip-flops, counters, registers, decoders, multiplexers) are used wherever information is processed as binary signals:
- Computers and microprocessors – arithmetic, memory, control units.
- Digital instruments – frequency counters, digital voltmeters and multimeters, time-interval meters.
- Digital clocks and timers, stopwatches, multiplexed displays.
- Communication – multiplexing, encoding/decoding, error detection (parity), digital switching.
- Control systems – traffic light controllers, vending machines, industrial PLCs.
- Consumer products – calculators, mobile phones, digital TV and cameras.
Frequency counter
A frequency counter counts the number of cycles of an input signal during a precise gate time ; then . With s the count equals the frequency in Hz.
Input ─> Schmitt ─> ┌─────┐ ┌─────────┐
trigger │ AND │─> │ Decade │
└─────┘ │counters │
^ └────┬────┘
Crystal ─> Divider ─> gate v
(1 s gate, latch/reset) Latch ─> Decoder ─> Display
Operation
- The Schmitt trigger shapes the input into one clean pulse per cycle.
- A crystal oscillator and divider chain give an accurate gate pulse (e.g. 1 s).
- The AND gate lets input pulses reach the decade counters only during the gate time.
- At the end of the gate, the count is transferred to the latch and shown through BCD-to-7-segment decoders; the counters are then reset for the next reading.
Example: 50,000 pulses counted in a 1 s gate means kHz.
Questions from Old Question Collection (EX 502) (IOE EX 502 exam papers (BEL/BEX/BCT II/I) from 2068 to 2081) and Old Question Collection (BEI, EX 401) (IOE EX 401 exam papers (BEI I/I) from 2075 to 2082). Answers are written for this site; check them against your class notes.
Chapter titles and hours from the IOE syllabus ↗