- 2078 Kartik · 2+2 marks
Flow through partially and fully submerged orifice
Short answer
For fully submerged orifice, Q = Cd a √(2g(H1-H2)) where H1, H2 are upstream and downstream heads. Partially submerged flow sums free part Q1 = (2/3)Cd b √(2g)[H^(3/2) - H1^(3/2)] and submerged part Q2 = Cd b (H2 - H) √(2gH), where H is the level difference, H1 top edge, H2 bottom edge.
Derive an expression for flow through partially and fully submerged orifice.
A submerged orifice discharges below the surface of the liquid on the downstream side. It may be fully or partially submerged.
Fully submerged orifice
Let the upstream and downstream liquid surfaces be at heights and above the centre of the orifice, and . Apply Bernoulli between a point in the upstream tank (negligible velocity) and the vena contracta, where the pressure is the downstream hydrostatic pressure :
With orifice area and coefficient of contraction , . Including the velocity coefficient gives :
The discharge depends only on the head difference.
Partially submerged orifice
Here the downstream level lies between the top and bottom edges of the orifice, and the flow is the sum of two parts.
Let be the width of the (rectangular) orifice, and the depths from the upstream surface to the top and bottom edges, and the difference between the upstream and downstream levels ().
- Free part (top edge to the downstream level): the pressure outside is atmospheric, so it behaves like a free rectangular orifice with the head varying from to :
- Submerged part (downstream level to bottom edge): height under the constant head difference :
Total discharge:
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ upstream level
| | |
| | H1
| | v ____ top edge
| H | | free part
H2 | | |
| v ~~~~~~~~~|~~~~|~~~~~~~ downstream level
| | | submerged part
v |____| bottom edge
✓ Answer checked by Claude Opus 5.5 (high effort)
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