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Derive surface tension and capillarity

Short answer

Surface tension σ causes excess pressure inside a droplet: Δp = 4σ/d (soap bubble: 8σ/d). Capillary rise balances surface tension with weight: h = (4σ cosθ)/(ρ g d). For water-glass θ≈0° gives rise; mercury θ≈130° gives depression.

Derive an expression for surface tension and capillarity.

Surface tension

Surface tension σ\sigma is the tensile force per unit length acting along the free surface of a liquid (N/m), due to cohesion between molecules.

Liquid droplet of diameter dd: the pressure force over the cut section balances the surface-tension force round its circumference:

Δp πd24=σ πd ⇒ Δp=4σd\Delta p\,\frac{\pi d^{2}}{4}=\sigma\,\pi d\ \Rightarrow\ \Delta p=\frac{4\sigma}{d}

For a soap bubble (two surfaces), Δp=8σd\Delta p=\dfrac{8\sigma}{d}.

Capillarity

In a vertical tube of diameter dd dipped in a liquid with contact angle θ\theta, the upward component of the surface-tension force round the circumference supports the weight of the raised column of height hh:

σcos⁡θ (πd)=ρg πd24 h\sigma\cos\theta\,(\pi d)=\rho g\,\frac{\pi d^{2}}{4}\,h h=4σcos⁡θρgdh=\frac{4\sigma\cos\theta}{\rho g d}

For water in glass θ≈0∘\theta\approx0^\circ (rise); for mercury θ≈130∘\theta\approx130^\circ so hh is negative (depression).

✓ Answer checked by Claude Opus 5.5 (high effort)

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