- Practice · 6 marks
BCC, FCC and HCP crystal structures
Short answer
BCC: 2 atoms/cell, R = (√3/4)a, CN = 8, APF = 0.68. FCC: 4 atoms/cell, R = (√2/4)a, CN = 12, APF = 0.74. HCP: 6 atoms/cell, ideal c/a = 1.633, CN = 12, APF = 0.74. FCC and HCP are close-packed, differing in stacking sequence (ABC vs AB).
Describe the BCC, FCC and HCP crystal structures. For BCC and FCC, determine the number of atoms per unit cell, the relation between atomic radius and lattice constant, the coordination number and the atomic packing factor.
Atomic packing factor (APF) is the fraction of the unit-cell volume occupied by atoms:
BCC (e.g., -Fe, Cr, W)
Atoms at the 8 corners and one at the body centre. Atoms touch along the body diagonal.
- Atoms per cell:
- Body diagonal , so
- Coordination number = 8
FCC (e.g., -Fe, Cu, Al, Ni)
Atoms at the 8 corners and the centre of each of the 6 faces. Atoms touch along the face diagonal.
- Atoms per cell:
- Face diagonal , so
- Coordination number = 12
HCP (e.g., Zn, Mg, Ti, Co)
Two hexagonal layers (top and bottom) with a central atom each, plus a triangular layer of 3 atoms midway between them. Atoms per cell = . Ideal axial ratio , coordination number 12, APF = 0.74.
| Structure | Atoms/cell | CN | APF |
|---|---|---|---|
| BCC | 2 | 8 | 0.68 |
| FCC | 4 | 12 | 0.74 |
| HCP | 6 | 12 | 0.74 |
FCC and HCP are both close-packed, differing in stacking sequence (ABCABC for FCC, ABABAB for HCP).
✓ Answer checked by Claude Opus 5.5 (high effort)
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