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- 2082 Chaitra (new course) · 2 marks
Fourier integral representation
Short answer
f(x) = (2/π) ∫₀^∞ (sin α cos αx)/α dα. The even function's Fourier integral reduces to cosine form with inner integral sin α/α over [0,1].
Find the Fourier integral representation of f(x) = 1 for |x| < 1; 0 for |x| > 1.
For f(x) defined on (−∞, ∞), the Fourier integral is f(x) = (1/π)∫₀^∞ ∫₋∞^∞ f(v) cos α(x − v) dv dα. Because the given f is even, this reduces to f(x) = (2/π)∫₀^∞ [∫₀^∞ f(v) cos αv dv] cos αx dα.
Inner integral. f(v) = 1 for |v| < 1 and 0 otherwise:
∫₀^∞ f(v) cos αv dv = ∫₀¹ cos αv dv = sin α / α
Representation
f(x) = (2/π) ∫₀^∞ (sin α cos αx / α) dα
This equals 1 for |x| < 1, 0 for |x| > 1, and 1/2 at x = ±1 (the average at the jump).
Putting x = 0 gives the useful result ∫₀^∞ (sin α / α) dα = π/2.
✓ Answer checked by Claude Opus 5.5 (high effort)
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