City class with operator overloading

Syntax of operator overloading

return_type ClassName::operator op (argument_list) { body }

operator is a keyword and op is the operator symbol. As a member function, a binary operator takes one argument (the right operand); the left operand is the calling object. c3 = c1 + c2; is translated to c3 = c1.operator+(c2);.

Program

Assumptions: operator+ returns a City whose DistFromKtm is the sum; operator- returns the distance between two cities (absolute difference) as a float. Approximate distances used: Pokhara 200 km, Dhangadi 680 km.

#include <iostream>
#include <cstring>
#include <cmath>
using namespace std;

class City {
    char CityName[20];
    float DistFromKtm;
public:
    void setName(const char *n)  { strcpy(CityName, n); }
    void setDist(float d)        { DistFromKtm = d; }
    const char* getName()        { return CityName; }
    float getDist()              { return DistFromKtm; }

    // sum of distances from Kathmandu
    City operator+(City c) {
        City t;
        strcpy(t.CityName, "Sum");
        t.DistFromKtm = DistFromKtm + c.DistFromKtm;
        return t;
    }

    // distance between two cities (difference of DistFromKtm)
    float operator-(City c) {
        return fabs(DistFromKtm - c.DistFromKtm);
    }
};

int main() {
    City c1, c2, c3;
    c1.setName("Pokhara");  c1.setDist(200);
    c2.setName("Dhangadi"); c2.setDist(680);

    c3 = c1 + c2;
    cout << "Sum of DistFromKtm of " << c1.getName() << " and "
         << c2.getName() << " = " << c3.getDist() << " km" << endl;
    cout << "Distance between " << c1.getName() << " and "
         << c2.getName() << " = " << c2 - c1 << " km" << endl;
    return 0;
}

Output:

Sum of DistFromKtm of Pokhara and Dhangadi = 880 km
Distance between Pokhara and Dhangadi = 480 km