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Frame AFD, SFD, BMD (100 kN, inclined member)

Short answer

Support reactions: HA=0, VA=80.47 kN upward, VD=76.09 kN upward. Axial, shear and bending moment diagrams: AB parabolic, BC and CD linear. Maximum bending moment 152.19 kN·m at C on BC, tension on bottom side.

Draw axial force, shear force and bending moment diagram for a given loaded frame. Also write the salient features. [Figure: hinged support at A at the lower left; inclined member A-B rising to B (slope 3 vertical to 4 horizontal; horizontal projection 2 m, rise 2 m shown) and carrying a 20 kN/m distributed load along it; horizontal member B-C-D with a 100 kN point load at C; B to C 2 m, C to D 2 m; D is the right end, supported as drawn.]

Assumptions (taken from the figure):

  • A(0,0) hinged; AB inclined, horizontal projection 2 m and rise 2 m, so B = (2, 2); BC = CD = 2 m horizontal.
  • 20 kN/m acts vertically downward on the full inclined length AB (2.83 m, total 56.57 kN); 100 kN downward at C.
  • D is taken as a roller (vertical reaction only), which makes the frame determinate.

Sign convention: N is positive in tension; V is positive when the forces on the part before the section (travelling A → end) point along the left-hand normal of the member axis (upward on a left-to-right beam); M is quoted as a magnitude with the tension face named. Support reactions are drawn on the free-body of the whole frame.

              /B--------------C--------------D
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A

Support reactions

Equilibrium of the whole frame gives ΣFx=0\Sigma F_x = 0, ΣFy=0\Sigma F_y = 0 and ΣM=0\Sigma M = 0.

  • HAH_A = 0.00 kN ←
  • VAV_A = 80.47 kN ↑
  • VDV_D = 76.09 kN ↑

Check: the three equilibrium equations of the complete frame (and the hinge condition, where present) are satisfied to rounding (residuals below 10−910^{-9}).

Axial force, shear force and bending moment at the key sections

SectionN (kN)V (kN)M (kN·m)
AB at A-56.9056.900.00
AB at B-16.9016.90104.38 (right face)
BC at B0.0023.91104.38 (bottom)
BC at C0.0023.91152.19 (bottom)
CD at C0.00-76.09152.19 (bottom)
CD at D0.00-76.090.00

Shape of the diagrams

  • AB: V linear, M parabolic
  • BC: V constant (steps at point loads), M linear
  • CD: V constant (steps at point loads), M linear
  • AFD: constant between loads on a member, changing only where a load component acts along the member.
  • BMD is drawn on the tension side of each member; it is continuous at rigid joints (moment is transferred) and zero at hinges and at free ends.

Salient features

  • Maximum bending moment = 152.19 kN·m at C (on BC), tension on the bottom

✓ Answer checked by Claude Opus 5.5 (high effort)

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