- 2080 Bhadra · 14 marks
Frame AFD, SFD, BMD (15 kN/m, 75 kN)
Short answer
The frame has a hinge at mid-BC. Support reactions: H_A=25.55 kN→, V_A=91.94 kN↑, H_D=49.45 kN→, V_D=13.06 kN↑. Axial force constant on each member (e.g., AB -91.94 kN). Shear constant on AB (-25.55 kN), linear on BC, steps at 75 kN load on CD. Maximum bending moment 204.38 kN·m at B; local maximum on BC 34.44 kN·m. BMD is drawn on tension side.
Draw axial force, shear force and bending moment diagram for the given frame. [Figure: left column A-B of height 8 m with A hinged at the base; inclined member B-C rising 2 m over a horizontal span of 7 m and carrying a 15 kN/m UDL; right column C-D of height 8 m (D hinged at the base); a 75 kN horizontal force acts on the right column at 3 m from the base; overall width 7 m.]
Assumptions (taken from the figure):
- A(0,0) hinged; AB = 8 m, so B = (0, 8). B to C (7, 10) is inclined (rises 2 m in 7 m, length 7.28 m). The right column CD is 8 m high, so the hinged support D = (7, 2) is 2 m above the level of A.
- With two hinged supports and no internal hinge the frame is indeterminate, so a hinge is assumed at the middle of BC, (3.5, 9), giving a three-hinged frame.
- 15 kN/m acts downward per metre of horizontal projection of BC (total 105 kN); the 75 kN horizontal force acts to the left on CD, 3 m above D, i.e. at (7, 5).
Sign convention: N is positive in tension; V is positive when the forces on the part before the section (travelling A → end) point along the left-hand normal of the member axis (upward on a left-to-right beam); M is quoted as a magnitude with the tension face named. Support reactions are drawn on the free-body of the whole frame.
---C
----- |
------- |
B-- |
| |
| |
| |
| |
| |
| D (2 m above A)
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A
Support reactions
Moments about A: . Hinge at the middle of BC (left part): . With () and ():
- = 25.55 kN →
- = 91.94 kN ↑
- = 49.45 kN →
- = 13.06 kN ↑
Check: moments of the right part about the hinge: ✓
Axial force, shear force and bending moment at the key sections
| Section | N (kN) | V (kN) | M (kN·m) |
|---|---|---|---|
| AB at A | -91.94 | -25.55 | 0.00 |
| AB at B | -91.94 | -25.55 | -204.38 (left face) |
| BC at B | -49.82 | 81.39 | -204.38 (top) |
| BC at hinge (3.64 m from B) | -35.40 | 30.91 | 0.00 |
| BC at C | -20.98 | -19.57 | 20.63 (bottom) |
| CD at C | -13.06 | 25.55 | 20.63 (left face) |
| CD just above the 75 kN load | -13.06 | 25.55 | 148.36 (left face) |
| CD just below the 75 kN load | -13.06 | -49.45 | 148.36 (left face) |
| CD at D | -13.06 | -49.45 | 0.00 |
Shape of the diagrams
- AB: V constant, M linear
- BC: V linear, M parabolic
- CD: V constant on each side of the 75 kN load (it steps by 75 kN there), M linear on each side
- AFD: constant between loads on a member, changing only where a load component acts along the member.
- The BMD is drawn on the tension side of each member; it is continuous at rigid joints (moment is transferred) and zero at hinges and at free ends.
Salient features
- Maximum bending moment = 204.38 kN·m at joint B (left face of AB, top of BC)
- V = 0 at 5.87 m from B along BC (5.64 m horizontally): M = 34.44 kN·m (bottom), the local maximum
- The moment on BC changes sign only at the internal hinge (3.64 m from B), where M = 0
- On CD the moment is 20.63 kN·m at C and 148.36 kN·m at the 75 kN load, falling to 0 at D (tension on the left, inner face)
✓ Answer checked by Claude Opus 5.5 (high effort)
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