- Asked 2/25
- 2081 Baisakh · 8 marks
- 2068 Baisakh (old course) · 8 marks
Stepwise procedure of Mohr's circle
Short answer
Draw σ-τ axes; plot X(σx, τxy) and Y(σy, −τxy) taking clockwise shear as positive. Centre C = ((σx+σy)/2, 0); radius R = √[((σx−σy)/2)² + τxy²]. Draw the circle. For an inclined plane, rotate radius CX by 2θ to read σn and τθ. Principal stresses: OC±R; τmax = R.
Write down the stepwise procedure (with sketch) for the determination of stresses in inclined plane for General stresses conditions (, and are given) using the Mohr's circle method.
Mohr's circle is a graphical method that represents the state of plane stress at a point; every point on the circle gives the normal and shear stress on one plane.
Given: , and on an element, and a plane whose normal is at angle to the -axis.
Procedure
- Draw the -axis horizontally (tension positive, to the right of O) and the -axis vertically through O. Select a suitable scale.
- Sign rule for plotting shear: a shear stress that tends to turn the element clockwise is plotted above the -axis, and one that turns it anticlockwise is plotted below. With this rule, a rotation of on the circle is in the same sense as the rotation of the plane. Plot point for the face on which acts.
- Plot point for the perpendicular face (its shear turns the element the opposite way).
- Join X and Y. The line cuts the -axis at , the centre, where .
- With C as centre and as radius, draw the circle. Radius .
- The circle cuts the -axis at and : , . The angle gives the principal plane.
- For the stresses on the given inclined plane, rotate the radius CX through about C in the same sense as the plane is rotated, reaching point . The abscissa of Q is the normal stress and the ordinate is the shear stress . The diametrically opposite point gives the stresses on the perpendicular plane.
- The resultant stress is , and its obliquity is measured from the -axis.
- The top and bottom points of the circle give the maximum shear stress .
Sketch
tau
| T (tau max = R)
| .--*--.
| / | \
| *Q | * X(sx, txy)
--------+-P2-----C------P1------- sigma
O \ | /
| *Y | /
| '--*--'
| T'
P2 = sigma_2, P1 = sigma_1, angle XCP1 = 2*theta_p
✓ Answer checked by Claude Opus 5.5 (high effort)
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